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Rotation of a string k times with a complexity of k
Use string slicing to split the string into two parts and swap them k times
Complexity will be O(k) as we are swapping only k times
Example: 'hello' rotated 2 times becomes 'llohe'
Algo from leetcode No.56
I applied via Naukri.com and was interviewed in Jul 2024. There were 2 interview rounds.
An Armstrong number is a number that is equal to the sum of its own digits raised to the power of the number of digits.
Calculate the number of digits in the given number
Calculate the sum of each digit raised to the power of the number of digits
Check if the sum is equal to the original number
Armstrong numbers are numbers that are equal to the sum of their own digits raised to the power of the number of digits.
Iterate through the given range of numbers
Calculate the sum of each digit raised to the power of the number of digits
Check if the sum is equal to the original number, if yes then it is an Armstrong number
API responses can include success, error, informational, and redirection status codes.
Success responses typically have status code 2xx (e.g. 200 OK)
Error responses typically have status code 4xx or 5xx (e.g. 404 Not Found)
Informational responses have status code 1xx (e.g. 100 Continue)
Redirection responses have status code 3xx (e.g. 301 Moved Permanently)
Binary Search questions were asked
Peak in a mountain array question were asked
I applied via Naukri.com and was interviewed before Jun 2023. There were 2 interview rounds.
HackerRank, one graph question which I solved.
Algo from leetcode No.56
I applied via Company Website and was interviewed in Oct 2023. There was 1 interview round.
I was interviewed in Mar 2017.
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