Juniper Networks Software Engineer Interview Questions, Process, and Tips

Q1. Explain which are IPC mechanism
Ans. 
IPC mechanisms are used for inter-process communication in software development.
• IPC mechanisms allow processes to communicate with each other, either on the same machine or across a network.

• Common IPC mechanisms include pipes, message queues, shared memory, sockets, and signals.

• Examples of IPC mechanisms include using sockets for network communication between client and server applications, or using shared memory for c...read more
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Q1. Explain the Socket communication
Ans. 
Socket communication is a method of communication between two processes on a network using sockets.
• Socket communication involves a client and a server communicating over a network.

• It uses TCP or UDP protocols to establish a connection.

• Data is exchanged through sockets using read and write operations.

• Sockets can be used for various applications like web browsing, email, and file transfer.
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Q1. They asked OS fundamentals
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Q1. I2c Spi protocol implementation
Ans. 
I2C and SPI are serial communication protocols used for connecting microcontrollers to peripherals.
• I2C (Inter-Integrated Circuit) is a synchronous, multi-master, multi-slave, packet-switched protocol commonly used for communication between integrated circuits.

• SPI (Serial Peripheral Interface) is a synchronous, full-duplex, master-slave communication protocol commonly used for communication between microcontrollers and ...read more
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Q1. Last company experience and details
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Q1. Shared memory, threading , synchronization mechanism
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Q1. Create your own hashmap
Ans. 
Implement a custom hashmap in Java
• Create a class to represent the hashmap

• Use an array to store the key-value pairs

• Implement methods for put, get, and remove operations
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Q1. Subarray Sum divisible by K
Ans. 
Find the number of subarrays whose sum is divisible by K.
• Use prefix sum technique to calculate the sum of subarrays efficiently.

• Keep track of the remainders of prefix sums when divided by K.

• Use a hashmap to store the count of each remainder.

• For each prefix sum, check how many previous prefix sums have the same remainder.

• Add the count of subarrays with the same remainder to the total count.
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Q1. Interests and open to work from Bangalore
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Round duration - 40 minutes
Round difficulty - Easy

Technical round with questions based on DSA.

Q1. 
Reverse a Number Problem Statement
Create a program to reverse a given integer N. The output should be the reversed integer.
Note:
If a number has trailing zeros, their reversed version should not inclu...read more
Ans. 
Reverse a given integer while excluding trailing zeros.
• Create a program to reverse the given integer by converting it to a string and then reversing it.

• Remove any trailing zeros from the reversed string before converting it back to an integer.

• Handle the constraints of the input integer being between 0 and 10^8.

• Example: For input 1230, the output should be 321.
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Q2. 
Reverse a Linked List Problem Statement
You are given a Singly Linked List of integers. Your task is to reverse the Linked List by changing the links between nodes.
Input:
The first line of input contai...read more
Ans. 
Reverse a given singly linked list by changing the links between nodes.
• Iterate through the linked list and reverse the links between nodes.

• Use three pointers to keep track of the current, previous, and next nodes.

• Update the links while traversing the list to reverse it.

• Return the head of the reversed linked list.
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Q3. What is the difference in C++ between 'new int[5]' and 'malloc(5 * sizeof(int))'?
Ans. 
new int[5] is C++ specific and initializes the array with default values, while malloc(5 * sizeof(int)) is a C function and does not initialize the array.
• new int[5] is C++ specific and calls constructors for each element in the array.

• malloc(5 * sizeof(int)) is a C function and does not call constructors, leaving the array uninitialized.

• new int[5] returns a pointer to the first element of the array, while malloc(5 * siz...read more
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