Qualcomm Software Engineer Interview Questions, Process, and Tips

Aptitude and technical questions were asked

Q1. Pattern question
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Q2. Doubly linked list insertion
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Q1. C++ linked lists
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Q2. Resume based, projects were asked.
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First round-aptitute and technical questions from C,OS,DBMS

Q1. What are the types of caching mechanisms?
Ans. 
Types of caching mechanisms include browser caching, server-side caching, and content delivery network (CDN) caching.
• Browser caching: storing web page resources locally on a user's device to reduce load times on subsequent visits.

• Server-side caching: storing data in memory on the server to reduce the need to fetch data from the database repeatedly.

• Content Delivery Network (CDN) caching: caching content on servers distr...read more
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Q2. Explain the physical memory and virtual memory
Ans. 
Physical memory refers to the actual RAM installed in a computer, while virtual memory is a memory management technique that uses disk space as an extension of RAM.
• Physical memory is the actual hardware component where data is stored temporarily for quick access by the CPU.

• Virtual memory is a memory management technique that allows the operating system to use disk space as an extension of physical memory.

• Physical memor...read more
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Q1. It was a dsa coding question
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Q1. Its was also dsa coding ques
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Q1. Detect endianness using C program
Ans. 
Detect endianness using C program
• Use a union to create a variable with a known value

• Check the value of the first byte to determine endianness

• Big endian systems store the most significant byte first

• Little endian systems store the least significant byte first

• Example: union { int i; char c; } u; u.i = 1; if (u.c == 1) { /* Little endian */ } else { /* Big endian */ }
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Q2. Count set bits using C
Ans. 
Count set bits in a number using C programming language.
• Use bitwise AND operation with 1 to check if the rightmost bit is set.

• Shift the number to the right by 1 bit each time to check all bits.

• Repeat the process until the number becomes 0, counting the set bits each time.
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