AGS Health Interview Questions and Answers

The minimum number of towers required to cover all houses.

• Iterate through the houses and find the maximum distance between any two adjacent houses.

• Divide this maximum distance by the range of each tower to get the minimum number of towers required.

• If there is a remainder, add one to the result.

• Return the minimum number of towers.

Find minimum deletions to make a sequence sorted.

• Count the number of elements that are not in increasing order.

• Subtract the count from the length of the sequence to get the minimum deletions.

• Use dynamic programming to optimize the solution.

• Time complexity: O(nlogn) using binary search.

Find the maximum number in the subarrays of length k.

• Iterate through the array and keep track of the maximum number in each subarray of length k.

• Use a sliding window approach to efficiently find the maximum number in each subarray.

• Time complexity can be optimized to O(n) using a deque data structure.

Find the length of the longest valid parentheses substring in a given string.

• Use a stack to keep track of the indices of opening parentheses.

• Iterate through the string and update the maximum length of valid parentheses.

• Handle cases where closing parentheses are encountered without a matching opening parentheses.