TCS Software Development Engineer Intern Interview Questions, Process, and Tips

All kind of basic aptitude to oops

Two java questions easy and medium

Q1. Find the starting point of linked list
Ans. 
Traverse the linked list to find the starting point by using Floyd's Tortoise and Hare algorithm
• Use two pointers, slow and fast, to traverse the linked list

• Move slow pointer by one step and fast pointer by two steps

• When they meet, reset one pointer to the head and move both pointers by one step until they meet again
Answered by AI
Add your answer
Q2. Find the length of linked list
Ans. 
Traverse the linked list and count the number of nodes
• Initialize a counter variable to 0

• Traverse the linked list while incrementing the counter for each node

• Return the final count as the length of the linked list
Answered by AI
Add your answer

Good aptitute is asked in the tcs

Basic to medium level question

Q1. Java oops features
Add your answer
Q2. Explain oops features
Ans. 
OOPs features include encapsulation, inheritance, polymorphism, and abstraction.
• Encapsulation: Bundling data and methods that operate on the data into a single unit (class).

• Inheritance: Ability to create new classes based on existing classes, inheriting their attributes and methods.

• Polymorphism: Ability to use a single interface to represent different data types or objects.

• Abstraction: Hiding the implementation details...read more
Answered by AI
Add your answer
Q3. Why string is immutable
Ans. 
String is immutable in order to ensure data integrity and security.
• Immutable strings prevent accidental modification of data.

• Immutable strings allow for safe sharing of data between different parts of a program.

• Immutable strings help in thread safety by avoiding concurrent modification issues.

• Example: String str = "hello"; str.concat(" world"); // This does not modify the original string, but creates a new one
Answered by AI
Add your answer
Q4. What is difference between string and string builder
Ans. 
String is immutable while StringBuilder is mutable in Java.
• String is immutable, meaning once created, it cannot be changed. StringBuilder is mutable, allowing for modifications.

• String concatenation creates a new string object each time, while StringBuilder allows for efficient string manipulation.

• StringBuilder is more efficient for concatenating multiple strings in a loop.

• Example: String str = "Hello"; StringBuilder sb...read more
Answered by AI
Add your answer