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JPMorgan Chase & Co.
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I was interviewed in Jan 2025.
posted on 13 Nov 2024
Coding test was asked in a live interactive session
Asynchronous communication design involves decoupling components to allow them to operate independently and communicate without blocking each other.
Decide on the communication protocol (e.g. REST, messaging queues)
Implement error handling and retries for robustness
Use callbacks, promises, or async/await for handling asynchronous operations
Consider scalability and performance implications of asynchronous design
There were three coding questions.
I applied via Naukri.com and was interviewed in Nov 2024. There was 1 interview round.
I applied via Company Website and was interviewed in Nov 2024. There were 2 interview rounds.
posted on 31 Oct 2024
I applied via Naukri.com and was interviewed in Oct 2024. There was 1 interview round.
Question Related to the DP and the Graph
Find the Kth maximum element in an array of strings.
Sort the array in descending order.
Return the element at index K-1.
Coin change problem can be solved using dynamic programming to find the minimum number of coins needed to make a certain amount of change.
Use dynamic programming to build up solutions for smaller subproblems
Start by initializing an array to store the minimum number of coins needed for each amount from 0 to the target amount
Iterate through each coin denomination and update the array with the minimum number of coins need
MCQ test consisting of 70 mcqs in 75 minutes from aptitude english and cs fundamentals. If cleared next paper 2 coding qs medium level
I faced challenges with integrating third-party APIs and debugging complex logic.
Difficulty in understanding and implementing third-party APIs
Issues with data synchronization between different systems
Troubleshooting complex logic errors
Managing dependencies and version conflicts
Time constraints affecting problem-solving
posted on 1 Oct 2024
I applied via Campus Placement
DP graphs strings it was good
Reverse a linked list by changing the direction of pointers
Start with three pointers: current, previous, and next
Iterate through the list, updating pointers to reverse the direction
Return the new head of the reversed list
The Fibonacci series is a sequence of numbers where each number is the sum of the two preceding ones.
Start with two variables initialized to 0 and 1
Loop through desired number of iterations, adding the previous two numbers to get the next number
Print or store each number in the series
I want to switch to explore new technologies and challenges in a different industry.
Interested in learning new skills and technologies
Seeking new challenges and opportunities for growth
Want to explore different industry perspectives
based on 1 interview
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