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I applied via Approached by Company and was interviewed in Feb 2024. There were 2 interview rounds.
I have over 10 years of experience working on various projects in the field of engineering.
Led a team in designing and implementing a new software system for a major tech company
Managed a project to upgrade manufacturing processes, resulting in a 20% increase in efficiency
Collaborated with cross-functional teams to develop a new product from concept to launch
Technical round with simple DSA question
Technical round with Hiring manager
I am passionate about advancing technology and contributing to a leading company in the industry.
Exciting opportunity to work on cutting-edge projects
Chance to collaborate with talented professionals
Desire to make a significant impact in the industry
Opportunity for career growth and development
I applied via Referral and was interviewed before Dec 2020. There were 4 interview rounds.
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I applied via Naukri.com and was interviewed before Dec 2019. There were 5 interview rounds.
I applied via Walk-in and was interviewed before Aug 2020. There was 1 interview round.
I applied via Naukri.com and was interviewed in Oct 2021. There were 2 interview rounds.
They ask to many technical question and ask to code also
They ask for your background and thing you learnt in your past
I applied via Campus Placement and was interviewed before Feb 2023. There were 2 interview rounds.
It was 1 coding question with 10 test cases. They asked a question based on binary search. I got 3 hrs to clear that test. I went in as a campus fresher. For lateral joinees, it is a much more difficult question that you have to clear in 4hrs.
The best way to find the majority element in an array is by using the Boyer-Moore Voting Algorithm.
Initialize a candidate variable and a count variable.
Iterate through the array and for each element:
- If the count is 0, set the current element as the candidate.
- If the current element is the same as the candidate, increment the count.
- Otherwise, decrement the count.
After the iteration, the candidate will be the ...
Reverse a linked list in K groups
Iterate through the linked list in groups of size K
Reverse each group of nodes using a temporary pointer
Connect the reversed groups to form the final reversed linked list
1. Revere Linked List
2. Maximum water in a container
ArrayList is a resizable array implementation in Java. Appium locators include ID, name, class name, xpath, etc. UI Automator 1 and 2 are tools for testing Android apps.
ArrayList is a dynamic array that can grow or shrink in size. Example: ArrayList<String> list = new ArrayList<>();
Appium locators include ID, name, class name, xpath, etc. Example: driver.findElement(By.id("elementID"));
UI Automator 1 is a t...
1. What is same for you and even for PM of US?
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