VMware Software Mts Software Engineer Interview Questions, Process, and Tips

Q1. Given two strings s1 and s2 find the missing character with TC: 0(n) and SC: O(1)
Ans. 
Find the missing character in two strings with linear time complexity and constant space complexity.
• Iterate through both strings simultaneously and XOR the ASCII values of characters.

• The missing character will be the XOR result with the ASCII value of the last character in the longer string.

• Example: s1 = 'abcd', s2 = 'abcde', missing character is 'e'.
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Q2. Find the target value in sorted rotated array
Ans. 
Search for target value in a sorted rotated array efficiently.
• Use binary search to find the pivot point where the array is rotated.

• Then perform binary search on the appropriate half of the array to find the target value.

• Handle cases where the target value is at the pivot point or not found.
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Q1. What are decorators in Python and how define it. and what is a function object
Ans. 
Decorators in Python are functions that modify the behavior of other functions. Function objects are objects that can be assigned to variables, passed as arguments, and returned from other functions.
• Decorators are used to add functionality to existing functions without modifying their code.

• They are defined using the @ symbol followed by the decorator function name above the function definition.

• Function objects in Pytho...read more
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Q2. Sort Zeros in the end of the array
Ans. 
Sort zeros to the end of the array of strings
• Iterate through the array and move all zeros to the end

• Use two pointers approach to swap elements

• Example: Input: ['1', '0', '3', '0', '5'], Output: ['1', '3', '5', '0', '0']
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Q1. Explain OOPS Concepts
Ans. 
OOPS concepts refer to Object-Oriented Programming principles like Inheritance, Encapsulation, Polymorphism, and Abstraction.
• Inheritance: Allows a class to inherit properties and behavior from another class.

• Encapsulation: Bundling data and methods that operate on the data into a single unit.

• Polymorphism: Ability to present the same interface for different data types.

• Abstraction: Hiding the complex implementation detail
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Q2. Java Multi threading
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Techinical questions were asked and basic oops

Q1. Oops was asked in it
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Q2. Dsa was asked in it
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