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I was interviewed in Jan 2025.
1. Explain about framework architecture and from that all questions derived. asked to write diagram and explain the structure.
2. Difference between class variable and instance variable.
3. what is ITestListener why used and when used in framework.
4. architecture of selenium 4 (geckodriver, chromium driver)
5. what is BDD and cucumber, how both are related to.
6. which kind of framework you go, either POM or Page factory for with testNg/junit?
7. asked to write query on sql joins and how you fetch the second lowest of salary from each department.
8. DDL, DML statements.
9. pathquery and query parameters differences(API)
10. How the responses you are validating in automation framework for Json response file.
11. status code of Https
12. serialization and deserialization difference
13. String Builder, String Buffer and String difference? which is better and which is safe to use.
14. Dropdown in selenium how you handle, how to check which is already selected?
15. multiple data provider in testng and how you pass parameter and how you retrive from excel sheet? Asked to write code!
16.what is flaky testing?
17.Asked to write first code of JDBC connecting establishment with framework.
18. Code execution: input ="aabbabcbb"; output = a:3 , b:5, c:1 like this if they give name also it should count. Tip : HashMap you can write the code.
19. Code execution: a[]={1,2,3,4,0,0,0} b={5,6,7} output need to print as remove all 0's from first array and replace 1,2,3,4 with 5,6,7 some crazy questions.
20. Git cmds and CI/CD tool.
1. asked about architecture and where you used oops concepts?
2. abstract class and interfaces
3. select drop down all options
4. find scrape links from webpage write the code
5. asked for writing xpath for any element random website.
6. asked about following-sibling, descendent and preceding-sibling, normalise-space locators.
7. jdbc connection code.
8. API JSON file - how you done validation in automation testing.
I was interviewed in Jan 2025.
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Example Question (Numerical Ability):
Question:
If 15% of a number is 45, what is 30% of that number?
Solution:
1. Find the number:
If 15% of a number is 45, then
\text{Number} = \frac{45}{0.15} = 300.
2. Calculate 30% of the number:
Now, 30% of 300 is
0.30 \times 300 = 90.
Answer:
30% of the number is 90.
---
Additional Example (Simple Interest):
Question:
A bank offers a simple interest rate of 5% per annum on a deposit of Rs.20,000. What will be the interest earned in 3 years?
Solution:
1. Use the simple interest formula:
\text{Simple Interest} = \frac{P \times R \times T}{100}
= Principal amount = Rs.20,000
= Rate of interest = 5%
= Time = 3 years
2. Calculate the interest:
\text{Interest} = \frac{20000 \times 5 \times 3}{100} = 3000.
Answer:
The interest earned in 3 years is Rs. 3000.
1. Quantitative Aptitude
Q: A sum of ₹10,000 is invested at 10% per annum simple interest. What is the interest after 3 years?
A: Interest = (P × R × T) / 100 = (10,000 × 10 × 3) / 100 = ₹3,000
2. Reasoning Ability
Q: If A is the father of B, but B is not the son of A, what is B’s relation to A?
A: Daughter
3. English Language
Q: Choose the correct sentence:
a) She don’t like coffee.
b) She doesn’t like coffee.
A: b) She doesn’t like coffee.
4. General Awareness (Banking GK)
Q: What does RBI stand for?
A: Reserve Bank of India
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Example Question (Numerical Ability):
Question:
A bank offers a simple interest rate of 6% per annum. If a customer deposits Rs. 25,000 for 4 years, what is the total simple interest earned over that period?
Solution:
1. Identify the formula for Simple Interest (SI):
\text{SI} = \frac{P \times R \times T}{100}
is the principal (Rs. 25,000)
is the rate of interest (6%)
is the time period (4 years)
2. Substitute the values into the formula:
\text{SI} = \frac{25000 \times 6 \times 4}{100}
3. Calculate the interest:
\text{SI} = \frac{25000 \times 24}{100} = \frac{600000}{100} = 6000.
Answer:
The total simple interest earned over 4 years is Rs. 6,000.
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Additional Example (Logical Reasoning):
Question:
In a sequence of numbers representing daily bank transactions, the amounts follow an arithmetic progression: 105, 115, 125, ... What will be the 8th transaction amount?
Solution:
1. Identify the first term and common difference:
First term,
Common difference,
2. Use the formula for the nth term of an arithmetic progression:
a_n = a_1 + (n - 1)d
3. Substitute :
a_8 = 105 + (8 - 1) \times 10 = 105 + 70 = 175.
Answer:
The 8th transaction amount is 175.
I was interviewed in Aug 2024.
The aptitude test will be conducted online.
I was interviewed in Jan 2025.
I was interviewed in Jan 2025.
A sequence was provided: 4181, 2684, 1597, 987, 610.
first 2 are given and write code for other value calculation using java 8
The second question required writing a reverse of a palindrome using both Java 8 streams. I was able to successfully write both and clear the first round.
posted on 4 Feb 2025
I was interviewed in Jan 2025.
I was interviewed in Jan 2025.
posted on 2 Feb 2025
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