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Its only one round that is Hr round and its lit easy
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I was interviewed in Nov 2024.
I applied via Company Website and was interviewed before May 2023. There was 1 interview round.
Spring Boot offers advantages like rapid development, easy configuration, embedded servers, production-ready features, and more.
Rapid development: Spring Boot simplifies the setup and configuration of Spring applications, allowing developers to focus on writing business logic.
Easy configuration: Spring Boot provides auto-configuration, reducing the need for manual setup and boilerplate code.
Embedded servers: Spring Boo...
I was interviewed before Apr 2021.
Round duration - 60 minutes
Round difficulty - Easy
Technical Interview round with 2 DSA problems.
You are provided with an undirected graph composed of 'N' vertices and 'M' edges, where vertices are labeled from 1 to 'N'.
Your task is to determine if...
DFS can be used to detect cycle in an undirected graph. Do a DFS traversal of the given graph. For every visited vertex ‘v’, if there is an adjacent ‘u’ such that u is already visited and u is not parent of v, then there is a cycle in graph.
If we don’t find such an adjacent for any vertex, we say that there is no cycle.
Pseudocode :
DetectCycle(graph, v, visited[], parent)
{
// mark the current node as visited
...
Given a binary tree, your task is to perform a zigzag level order traversal. This traversal starts from left to right on the first level, then switches to righ...
This problem can be solved using two stacks.
Assume the two stacks are current: currentlevel and nextlevel. We would also need a variable to keep track of the current level order(whether it is left to right or right to left). We pop from the currentlevel stack and print the nodes value. Whenever the current level order is from left to right, push the nodes left child, then its right child to the stack nextlevel.
Si...
Tip 1 : Must do Previously asked Interview as well as Online Test Questions.
Tip 2 : Go through all the previous interview experiences from Codestudio and Leetcode.
Tip 3 : Do at-least 2 good projects and you must know every bit of them.
Tip 1 : Have at-least 2 good projects explained in short with all important points covered.
Tip 2 : Every skill must be mentioned.
Tip 3 : Focus on skills, projects and experiences more.
I applied via Instahyre and was interviewed in Jan 2021. There were 5 interview rounds.
To find a loop in a linked list, we use Floyd's cycle-finding algorithm.
Floyd's cycle-finding algorithm uses two pointers, one moving at a rate of one node per iteration and the other moving at a rate of two nodes per iteration.
If there is a loop in the linked list, the two pointers will eventually meet at some node.
To find the starting point of the loop, we reset one of the pointers to the head of the linked list and ...
I applied via LinkedIn and was interviewed in Jul 2020. There was 1 interview round.
Cycle detection in a directed graph
Use Depth First Search (DFS) algorithm to detect cycles in a directed graph
Maintain a visited set to keep track of visited nodes
Maintain a recursion stack to keep track of nodes in the current DFS traversal
If a node is visited and is already in the recursion stack, then a cycle is detected
Zig Zag order traversal of a binary tree is a way to traverse the tree in a zigzag pattern.
Start from the root node and traverse the tree level by level.
For odd levels, traverse from right to left.
For even levels, traverse from left to right.
Use a stack to keep track of the nodes to be traversed.
Repeat until all nodes have been visited.
Query to find number of trains between 2 given stations in SQL design.
Use a JOIN statement to join the tables containing train and station information.
Filter the results based on the given stations.
Count the number of trains in the result set.
Consider the direction of travel and the order of the stations in the query.
Handle cases where there are no trains between the given stations.
I was interviewed in Jan 2021.
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