EPIKInDiFi Full Stack Developer Interview Questions and Answers

Q1. Leetcode Hard questions
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Q2. IPO Leetcode Hard
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30 min test on simple google form

Half hour conding round on basic javascript questions

One hour coding round on little bit intermediate javascript questions

The aptitude test mainly covered logical reasoning, quantitative aptitude, and basic programming concepts. Questions were of moderate difficulty, with some time-based problem-solving challenges. Practicing common aptitude topics like puzzles, numerical ability, and coding fundamentals can help in preparation.

The group discussion round focused on general topics related to technology, current affairs, and workplace scenarios. The evaluators were looking for clarity of thought, communication skills, and how well candidates could present their points while engaging with others. Staying confident and actively participating helped in getting selected.

Q1. General fit to profile filtration
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Q1. To the profile applied for
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Q2. Explain an actual component
Ans. 
An actual component is a reusable and modular piece of software that performs a specific function within a larger system.
• Components are often designed to be independent and can be easily integrated into different systems.

• Examples of components include buttons, input fields, and dropdown menus in a user interface.

• Components can have their own logic, styling, and functionality, making them versatile building blocks for s
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Q3. Design the architecture
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Designing the architecture for a software system involves planning the structure and components of the system.
• Identify the key components of the system and their interactions

• Choose appropriate technologies and frameworks for each component

• Consider scalability, performance, security, and maintainability

• Create a detailed diagram or documentation of the architecture
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Q1. Attitude towards work
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Q1. Discussed on my last salary
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It was online 60min test.

It was offline 30 min test.

Q1. Oops,dbms,css,html,dsa,java.
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Q2. It was very friendly .
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Q1. What are the 4 principles of oops?
Ans. 
The 4 principles of OOP are Inheritance, Encapsulation, Abstraction, and Polymorphism.
• Inheritance allows a class to inherit properties and behavior from another class.

• Encapsulation restricts access to certain components within a class, protecting the data.

• Abstraction hides complex implementation details and only shows the necessary features.

• Polymorphism allows objects to be treated as instances of their parent class.
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Q2. What is the difference between string buffer and string builder?
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String buffer is synchronized and thread-safe, while string builder is not synchronized and faster.
• String buffer is synchronized, making it thread-safe for use in multi-threaded environments.

• String builder is not synchronized, providing better performance in single-threaded applications.

• String builder is faster than string buffer due to lack of synchronization overhead.

• Example: StringBuffer sb = new StringBuffer(); Str
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Q3. Why strings are immutable?
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Strings are immutable in order to ensure data integrity and security.
• Immutable strings prevent accidental data modification, ensuring data integrity.

• Immutable strings enhance security by preventing unauthorized access or tampering.

• Immutable strings allow for more efficient memory management and optimization.

• Example: 'Hello' cannot be changed to 'Hella' directly, a new string must be created.
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Q4. What are the different types of exception in java?
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There are two types of exceptions in Java: checked exceptions and unchecked exceptions.
• Checked exceptions are checked at compile time and must be handled using try-catch or throws keyword.

• Unchecked exceptions are not checked at compile time and include RuntimeException and its subclasses.

• Examples of checked exceptions include IOException, SQLException, and ClassNotFoundException.

• Examples of unchecked exceptions include...read more
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Q5. Explain linear search algorithm.
Ans. 
Linear search is a simple searching algorithm that sequentially checks each element in a list until a match is found.
• Iterate through each element in the list

• Compare the current element with the target value

• Return the index if a match is found, otherwise return -1
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Q6. Difference between JDK jvm and jre
Ans. 
JDK includes JRE and development tools, while JRE includes only the Java Runtime Environment.
• JDK stands for Java Development Kit, which includes JRE and development tools like compilers and debuggers.

• JRE stands for Java Runtime Environment, which includes JVM and libraries necessary to run Java applications.

• JVM stands for Java Virtual Machine, which is responsible for executing Java bytecode.

• JDK is used for developing ...read more
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