Amazon Development Centre India SDE Intern Interview Questions and Answers for Freshers

1 hour long test, 1 easy and 1 medium leetcode problem + some apti questions.

Q1. Asked 1 codding question (Medium) * Next permutation of a number. Number was a time stamp (eg 11:55 PM)
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Q1. 3 medium leetcode questions from graphs, queue and dp.
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Easy lc or medium lc quest

Q1. Coding round only was
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2 hours mcqs from all cse related topics + 1 coding question

3 coding questions easy level

Q1. I do not remember
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Duration: 1hr+
Topics: 2 - coding questions(logic-based)
platform: Hackerank

Q1. Find the square root of a number using only 4 basic arithmetic operations (+,-,*,/) without using a power operator and inbuilt libraries. For numbers that are not perfect squares, print the integer part of...read more
Ans. 
Find square root of a number using basic arithmetic operations without power operator and inbuilt libraries.
• Use binary search to find the integer part of the square root

• Use long division method to find the decimal part of the square root

• Repeat the above steps until desired accuracy is achieved

• Handle edge cases like negative numbers and numbers less than 1
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Q2. Addition of two linked lists, and finallt return the result as a linked list
Ans. 
Addition of two linked lists and return the result as a linked list.
• Traverse both linked lists simultaneously

• Add corresponding nodes and carry over the sum

• Create a new linked list with the sum
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Q1. Count occurrences in sorted array
Ans. 
Count occurrences of a given element in a sorted array.
• Use binary search to find the first and last occurrence of the element.

• Subtract the indices to get the count.

• Handle edge cases like element not present in the array.
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Q2. Deepest left node in binary tree
Ans. 
Find the deepest left node in a binary tree.
• Traverse the tree recursively and keep track of the depth and whether the current node is a left node.

• If the current node is a leaf node and its depth is greater than the deepest left node found so far, update the deepest left node.

• Return the deepest left node found.

• Example: For the binary tree with root node 1, left child 2, and left child of 2 being 4, the deepest left node...read more
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This round had questions from various topics like DBMS, system design, OOPs, aptitude etc. with one coding ques.

This had 2 coding questions (medium level) and a digital HR round where we just have to use a slider to answer our best reaction to situations.

Q1. Implementation of Min Stack
Ans. 
Implement a stack that supports push, pop, top, and retrieving the minimum element in constant time.
• Use two stacks - one to store the actual elements and another to store the minimum values.

• When pushing an element, check if it is smaller than the current minimum and push it to the min stack if so.

• When popping an element, check if it is the current minimum and pop from the min stack if so.

• Top operation can be implemente...read more
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Q2. Find leaf nodes in a binary tree ,followed by printing path to leaf nodes.
Ans. 
Find leaf nodes in a binary tree and print path to each leaf node.
• Traverse the binary tree using depth-first search (DFS)

• When reaching a leaf node, store the path from root to that leaf node

• Repeat the process for all leaf nodes in the tree
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Q1. DSA question to be solved
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2 DSA questions and 70 minutes.

Q1. Implement Min-stack using O(N) space .
Ans. 
Min-stack is implemented using O(N) space by keeping track of minimum value at each element.
• Use two stacks - one to store the actual elements and another to store the minimum value at each step.

• When pushing an element, check if it is smaller than the current minimum and update the minimum stack accordingly.

• When popping an element, also pop from the minimum stack if the popped element is the current minimum.
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Q2. Sliding Window Problem.
Ans. 
Sliding Window Problem involves finding a subarray of fixed size k with the maximum sum.
• Use a sliding window approach to iterate through the array and keep track of the sum of elements within the window.

• Slide the window by removing the first element and adding the next element in each iteration.

• Keep track of the maximum sum found so far and update it if a new maximum is found.
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