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I applied via Referral and was interviewed in Jan 2023. There were 5 interview rounds.
3 question based on data structures and algorithms of in which 1 was easy level and the other two were medium level
2 question again based on DSA, this was slightly good question based on tree and graph
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posted on 1 Feb 2025
I was interviewed in Jan 2025.
One mcq two codes in total 240 min
posted on 10 Oct 2024
I applied via Naukri.com and was interviewed in Sep 2024. There were 2 interview rounds.
I applied via Naukri.com and was interviewed in May 2024. There was 1 interview round.
posted on 13 Dec 2024
posted on 7 Oct 2024
I applied via LinkedIn and was interviewed in Sep 2024. There was 1 interview round.
I applied via LinkedIn and was interviewed in Mar 2024. There was 1 interview round.
There were 3 question from DSA: 1st and 2nd was from recession and Dp and last one was from graph.
posted on 3 Apr 2024
Some questions about specific puthon types etc...
I applied via LinkedIn and was interviewed before Mar 2023. There were 4 interview rounds.
I was given a problem statement and was asked to give a LLD and solution implementation and share it on Git.
The LLD submitted is a detailed design document outlining the architecture and implementation details of the software solution.
LLD stands for Low Level Design and includes detailed design diagrams, data structures, algorithms, and component interactions.
The LLD submitted should provide a clear roadmap for developers to implement the software solution based on the high-level design.
It should cover all aspects of the sof...
To add more features in the solution, consider user feedback, market trends, and technical feasibility.
Gather user feedback to understand what features are desired
Research market trends to identify popular features
Assess technical feasibility to determine if new features can be implemented
Prioritize features based on impact and resources available
I was interviewed in Jan 2022.
Round duration - 90 minutes
Round difficulty - Medium
Determine if a given singly linked list of integers forms a cycle or not.
A cycle in a linked list occurs when a node's next
points back to a previous node in the ...
The task is to determine if a given singly linked list forms a cycle or not.
A cycle occurs when a node's next points back to a previous node in the list.
To solve this problem, we can use the Floyd's Cycle-Finding Algorithm.
The algorithm uses two pointers, one moving at a normal pace and the other moving twice as fast.
If there is a cycle, the fast pointer will eventually catch up to the slow pointer.
If the fast pointer ...
Round duration - 60 minutes
Round difficulty - Medium
Determine the minimum depth of an integer-based binary tree. The minimum depth is defined as the number of nodes present along the shortest path from the root node down to t...
The minimum depth of a binary tree is the number of nodes along the shortest path from the root node down to the nearest leaf node.
The minimum depth can be found by performing a breadth-first search (BFS) traversal of the binary tree
During the BFS traversal, keep track of the current level and increment the depth by 1 for each level
Stop the BFS traversal when a leaf node is encountered and return the depth as the minim
Given two arrays A
and B
with sizes N
and M
respectively, both sorted in non-decreasing order, determine their intersection.
The intersection of two arrays in...
The problem is to find the intersection of two sorted arrays.
Use two pointers to iterate through the arrays.
Compare the elements at the current pointers and move the pointers accordingly.
If the elements are equal, add it to the intersection array and move both pointers.
If the element in the first array is smaller, move the first pointer.
If the element in the second array is smaller, move the second pointer.
Repeat until...
A mutex is a binary semaphore used for mutual exclusion, while a semaphore is a generalized synchronization primitive.
Mutex is used to protect a critical section of code, allowing only one thread to access it at a time.
Semaphore is used to control access to a shared resource, allowing multiple threads to access it simultaneously.
Mutex has ownership, meaning the thread that locks it must unlock it.
Semaphore does not hav...
Round duration - 60 minutes
Round difficulty - Easy
Round duration - 25 minutes
Round difficulty - Easy
Tip 1 : Practice a lot of DSA questions on various online platforms.
Tip 2 : Regularly go back to some of the typical DSA questions.
Tip 3 : Give equal importance to OS, OOPS, and CN subjects.
Tip 1 : Be thorough with your resume to answer anything and everything from your resume.
Tip 2 : Do not put false information on your resume.
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