Prodapt Software Trainee Interview Questions and Answers

Simple aptitude test was arranged that was online.

2 coding questions in any language.

Q1. About java basic core java concepts like opps, multi threading, collections, exception handeling.
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Q1. Simple introduction about me was asked and why I want to join this company.
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Q1. Js basic questions
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Q2. Angular questio s
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This round if the count is more they will have it or less means they will have one to one technical round

Q1. It will be like technical round
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Q1. For document verifications
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Q1. Implement LinkedList and insert element at last
Ans. 
Implement LinkedList and insert element at last
• Create a Node class with data and next pointer

• Create a LinkedList class with head and tail pointers

• Implement a method in LinkedList class to insert element at the end
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Arrays questions medium and easy

Q1. Thinking abilities
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Q1. Basic conversation
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Moderate level Aptitude test...........

Q1. Technical round was on coding part. I was asked more about OOPS concepts. I was also asked to write a program in C
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Q1. ...... .... ...... .... ..... ... ... .... ..... ... He hv he yr TV be ez HQ is Bts oct is ev
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Q1. Pillar of java with example
Ans. 
Four pillars of Java are Abstraction, Encapsulation, Inheritance, and Polymorphism.
• Abstraction: Hiding implementation details and showing only necessary information.

• Encapsulation: Wrapping data and code into a single unit.

• Inheritance: Acquiring properties and behavior of a parent class by a child class.

• Polymorphism: Ability of an object to take many forms.

• Example: A car is an abstraction of a vehicle, encapsulating its...read more
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Q2. Collection based questions
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Round duration - 60 minutes
Round difficulty - Medium

Mcq + Data structures questions

Q1. 
Maximum Sum Subarray Problem Statement
Given an array of integers, find the maximum sum of any contiguous subarray within the array.
Example:
Input:
array = [34, -50, 42, 14, -5, 86]
Output:
137
Exp...read more
Ans. Brute Force Approach
1. Create a nested loop. The outer loop will go from i = 0 to i = n - k. This will cover the starting indices of all k-subarrays
2. The inner loop will go from j = i to j = i + k - 1. This will cover all the elements of the k-subarray starting from index i
3. Keep track of the maximum element in the inner loop and print it.
Space Complexity: O(1)Explanation:
O(1) because the extra space being used (looping vari...read more
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Round duration - 70 minutes
Round difficulty - Medium

Standard System Design round

Q1. Design a Doctor Appointment System and provide some test cases.
Ans. 
Tip 1 : Implement using OOPs 
Tip 2 : Try to tell your approach to the interviewer as much as you can side by side
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Round duration - 90 minutes
Round difficulty - Medium

Interview of DSA + OOPS + Databse(SQL query) + Operating System

Q1. 
Left View of a Binary Tree
Given a binary tree, your task is to print the left view of the tree. The left view of a binary tree contains the nodes visible when the tree is viewed from the left side.
Inpu...read more
Ans. Recursive Approach
This problem can be solved through recursion.We will maintain max_level variable which will keep track of maxLevel and will pass current level in recursion as argument. Whenever we see a node whose current level is more than maxLevel then we will print that node as that will be first node for that current level. Also update maxLevel with current level.
Space Complexity: O(n)Explanation:
O(N), where ‘N’...read more
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Q2. What is the difference between CHAR and VARCHAR2 data types in SQL?
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Q3. What are the various types of constructors in C++?
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Q4. What is the difference between overloading and overriding?
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Round duration - 60 minutes
Round difficulty - Easy

Hr round - normal hr questions + situational 

Thoughtworks community discussion

Q1. Why should we hire you?
Ans. 
Tip 1 : Read all Thoughtworks community page and be honest

Tip 2 : Be open-minded and answer whatever you are thinking, in these rounds I feel it is important to have opinion.

Tip 3 : The cross-questioning can go intense sometimes, think before you speak.
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