Evora IT Solutions Software Engineer Interview Questions and Answers

30 mins Aptitude Question

30 mins - 3 Coding Question

Q1. Describe Rest API
Ans. 
Rest API is a set of rules and conventions for building and interacting with web services using HTTP methods.
• Rest API stands for Representational State Transfer Application Programming Interface.

• It uses standard HTTP methods like GET, POST, PUT, DELETE to perform CRUD operations.

• RESTful APIs use URLs to access resources, and return data in JSON or XML format.

• Stateless communication allows for scalability and flexibilit...read more
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Q2. What is various Response code. Diffenrence b/w 200 & 201, 400 & 403
Ans. 
Response codes indicate the status of a HTTP request. 200 & 201 are success codes, while 400 & 403 are client error codes.
• 200 - OK: Request was successful

• 201 - Created: Request was successful and a new resource was created

• 400 - Bad Request: The server cannot process the request due to a client error

• 403 - Forbidden: The server understood the request, but refuses to authorize it
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Q1. RDBMS related questions asked
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Q2. SQL login building related questions
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60min of aptitude and coding test

2 questions on coding test

Basic aptitude questions and questions on React

Asked for printing patterns in a loop

Q1. Explain your code. Talked about projects, questions on array and a Water-jug problem puzzle question
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Q1. Asked about family and residence.
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Q1. 30min technical round
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Q2. Project manager round
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Q3. HR round for salary discussion
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Simple String or list releted questions for Arranging a string some conditions wise

Q1. Count number after decimal value What is decorator What is abstraction in python
Ans. 
To count number after decimal value in Python, use string manipulation or math module.
• Use string manipulation to count number of digits after decimal point

• Use math module to round off the number and then subtract the original number to get the digits after decimal point

• Example: num = 3.14159, str_num = str(num), decimal_index = str_num.index('.') + 1, digits_after_decimal = len(str_num) - decimal_index
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