TestingXperts Full Stack Developer Interview Questions, Process, and Tips

Q1. Not available, PFB
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Q2. Please find below
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Round duration - 90 minutes
Round difficulty - Medium

Q1. 
Cycle Detection in a Singly Linked List
Determine if a given singly linked list of integers forms a cycle or not.
A cycle in a linked list occurs when a node's next points back to a previous node in the ...read more
Ans. 
The task is to determine if a given singly linked list forms a cycle or not.
• A cycle occurs when a node's next points back to a previous node in the list.

• To solve this problem, we can use the Floyd's Cycle-Finding Algorithm.

• The algorithm uses two pointers, one moving at a normal pace and the other moving twice as fast.

• If there is a cycle, the fast pointer will eventually catch up to the slow pointer.

• If the fast pointer ...read more
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Round duration - 60 minutes
Round difficulty - Medium

Q1. 
Minimum Depth of a Binary Tree
Determine the minimum depth of an integer-based binary tree. The minimum depth is defined as the number of nodes present along the shortest path from the root node down to t...read more
Ans. 
The minimum depth of a binary tree is the number of nodes along the shortest path from the root node down to the nearest leaf node.
• The minimum depth can be found by performing a breadth-first search (BFS) traversal of the binary tree

• During the BFS traversal, keep track of the current level and increment the depth by 1 for each level

• Stop the BFS traversal when a leaf node is encountered and return the depth as the minim
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Q2. 
Intersection of Two Arrays Problem Statement
Given two arrays A and B with sizes N and M respectively, both sorted in non-decreasing order, determine their intersection.
The intersection of two arrays in...read more
Ans. 
The problem is to find the intersection of two sorted arrays.
• Use two pointers to iterate through the arrays.

• Compare the elements at the current pointers and move the pointers accordingly.

• If the elements are equal, add it to the intersection array and move both pointers.

• If the element in the first array is smaller, move the first pointer.

• If the element in the second array is smaller, move the second pointer.

• Repeat until...read more
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Q3. What is the difference between a mutex and a semaphore?
Ans. 
A mutex is a binary semaphore used for mutual exclusion, while a semaphore is a generalized synchronization primitive.
• Mutex is used to protect a critical section of code, allowing only one thread to access it at a time.

• Semaphore is used to control access to a shared resource, allowing multiple threads to access it simultaneously.

• Mutex has ownership, meaning the thread that locks it must unlock it.

• Semaphore does not hav...read more
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Round duration - 60 minutes
Round difficulty - Easy

Round duration - 25 minutes
Round difficulty - Easy

String related functions,virtual functions and STL concepts

Q1. String related questions and STL concepts
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Round duration - 90 minutes
Round difficulty - Easy

Timing - 10AM-11:30AM
Online proctored test

Q1. 
Binary Tree Right View Problem Statement
Given a binary tree of integers, your task is to print the right view of it. The right view represents a set of nodes visible when the tree is viewed from the righ...read more
Ans. 
The task is to print the right view of a binary tree, representing nodes visible from the right side in top-to-bottom order.
• Traverse the tree level by level and keep track of the rightmost node at each level

• Print the rightmost node of each level to get the right view of the tree

• Use a queue for level order traversal and a map to store the rightmost nodes
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Q2. 
0/1 Knapsack Problem Statement
A thief is planning to rob a store and can carry a maximum weight of 'W' in his knapsack. The store contains 'N' items where the ith item has a weight of 'wi' and a value of...read more
Ans. 
Yes, the 0/1 Knapsack problem can be solved using dynamic programming with a space complexity of not more than O(W).
• Use a 1D array to store the maximum value that can be stolen for each weight from 0 to W.

• Iterate through each item and update the array based on whether including the item would increase the total value.

• The final value in the array at index W will be the maximum value that can be stolen.
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Round duration - 45 minutes
Round difficulty - Medium

Timing : 4PM-5PM
Environment - Online

There was a panel of 3 interviewers

Q1. How can you find the size of an array in C or C++ without using sizeof or any standard function?
Ans. 
You can find the size of an array in C or C++ by dividing the total size of the array by the size of one element.
• Calculate the total size of the array by multiplying the number of elements by the size of each element.

• Divide the total size by the size of one element to get the size of the array.

• For example, if you have an array of strings arr[] = {'hello', 'world', 'example'}, you can find the size by dividing the total
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Q2. Explain how indexing in a database works using B+ trees.
Ans. 
B+ trees are used for indexing in databases to efficiently search and retrieve data.
• B+ trees are balanced trees where each node can have multiple keys and child pointers.

• Data is stored in leaf nodes, while non-leaf nodes are used for navigation.

• B+ trees are commonly used in databases because of their ability to efficiently search and retrieve data.

• Example: In a database table with an index on a specific column, B+ tree...read more
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Round duration - 45 mintues
Round difficulty - Easy

Timing - 11AM-12:15PM
Environment - online video call

Again there was a panel of 2 senior engineers

Q1. 
Maximum Path Sum Problem Statement
You are given an n-ary tree consisting of 'N' nodes. Your task is to determine the maximum sum of the path from the root to any leaf node.
Example:
Input:
For the giv...read more
Ans. 
Find the maximum sum of the path from the root to any leaf node in an n-ary tree.
• Traverse the tree from root to leaf nodes while keeping track of the sum of each path.

• At each node, calculate the sum of the path from the root to that node and update the maximum sum found so far.

• Consider using depth-first search (DFS) or breadth-first search (BFS) for tree traversal.

• Handle cases where nodes have negative values or where
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