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Example Question (Numerical Ability):
Question:
If 15% of a number is 45, what is 30% of that number?
Solution:
1. Find the number:
If 15% of a number is 45, then
\text{Number} = \frac{45}{0.15} = 300.
2. Calculate 30% of the number:
Now, 30% of 300 is
0.30 \times 300 = 90.
Answer:
30% of the number is 90.
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Additional Example (Simple Interest):
Question:
A bank offers a simple interest rate of 5% per annum on a deposit of Rs.20,000. What will be the interest earned in 3 years?
Solution:
1. Use the simple interest formula:
\text{Simple Interest} = \frac{P \times R \times T}{100}
= Principal amount = Rs.20,000
= Rate of interest = 5%
= Time = 3 years
2. Calculate the interest:
\text{Interest} = \frac{20000 \times 5 \times 3}{100} = 3000.
Answer:
The interest earned in 3 years is Rs. 3000.
1. Quantitative Aptitude
Q: A sum of ₹10,000 is invested at 10% per annum simple interest. What is the interest after 3 years?
A: Interest = (P × R × T) / 100 = (10,000 × 10 × 3) / 100 = ₹3,000
2. Reasoning Ability
Q: If A is the father of B, but B is not the son of A, what is B’s relation to A?
A: Daughter
3. English Language
Q: Choose the correct sentence:
a) She don’t like coffee.
b) She doesn’t like coffee.
A: b) She doesn’t like coffee.
4. General Awareness (Banking GK)
Q: What does RBI stand for?
A: Reserve Bank of India
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Example Question (Numerical Ability):
Question:
A bank offers a simple interest rate of 6% per annum. If a customer deposits Rs. 25,000 for 4 years, what is the total simple interest earned over that period?
Solution:
1. Identify the formula for Simple Interest (SI):
\text{SI} = \frac{P \times R \times T}{100}
is the principal (Rs. 25,000)
is the rate of interest (6%)
is the time period (4 years)
2. Substitute the values into the formula:
\text{SI} = \frac{25000 \times 6 \times 4}{100}
3. Calculate the interest:
\text{SI} = \frac{25000 \times 24}{100} = \frac{600000}{100} = 6000.
Answer:
The total simple interest earned over 4 years is Rs. 6,000.
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Additional Example (Logical Reasoning):
Question:
In a sequence of numbers representing daily bank transactions, the amounts follow an arithmetic progression: 105, 115, 125, ... What will be the 8th transaction amount?
Solution:
1. Identify the first term and common difference:
First term,
Common difference,
2. Use the formula for the nth term of an arithmetic progression:
a_n = a_1 + (n - 1)d
3. Substitute :
a_8 = 105 + (8 - 1) \times 10 = 105 + 70 = 175.
Answer:
The 8th transaction amount is 175.
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