Belkin Interview Questions and Answers

The question is about finding the minimum steps to reach from a source string to a destination string using three operations.

• BFS and DFS are graph traversal techniques that can be used to solve this problem.

• BFS is typically used when finding the shortest path or exploring all possible paths in a graph.

• DFS is useful when searching for a specific path or exploring deeply into a graph.

• In this case, BFS can be used to find...read more

Find A-B of two sorted arrays A and B in O(m+n) time complexity.

• Create two pointers, one for each array, and compare the elements at those pointers.

• If the element in A is smaller, add it to the result array and move the A pointer forward.

• If the element in B is smaller, move the B pointer forward.

• Repeat until one of the pointers reaches the end of its array.

• Add any remaining elements in A to the result array.

• Time comple...read more

The routine should output the elements of the inorder traversal of a binary tree one by one in each call.

• Implement an inorder traversal algorithm recursively

• Use a global variable or pass a reference to keep track of the current element

• Call the routine repeatedly to get the next element in each call

Program to find minimum semesters required to complete courses with prerequisites

• Create a graph with courses as nodes and prerequisites as edges

• Use topological sorting to find the order of courses to be taken

• Calculate the minimum number of semesters based on the order obtained

• Handle cases where there are cycles in the graph

To find a loop in a directed graph, use Floyd's cycle-finding algorithm. To find the last element in a binary tree, traverse the tree and return the rightmost leaf node.

• For finding a loop in a directed graph, use Floyd's cycle-finding algorithm which uses two pointers moving at different speeds.

• To find the last element in a binary tree, traverse the tree recursively or iteratively and return the rightmost leaf node.

The question is about finding the last number in a circular queue that has the highest number of digits.

• Implement a circular queue data structure

• Iterate through the circular queue to find the last number with the highest number of digits

• Compare the number of digits of each number in the circular queue

• Keep track of the last number with the highest number of digits

Check if left child is less than right child in a binary tree

• Traverse the tree recursively and compare left and right child values

• Use a stack to traverse the tree iteratively and compare left and right child values

• Return true if all left children are less than right children, else false

Use built-in string method to check substring presence for faster execution.

• Use 'indexOf' method to check if substring is present in the main string.

• If the method returns -1, the substring is not present.

• If the method returns a non-negative integer, the substring is present.

To test if every left child's value is less than the right child's value in a binary tree.

• Traverse the binary tree using any traversal algorithm (e.g., in-order, pre-order, post-order)

• Compare the value of each left child with its right child

• If any left child's value is greater than or equal to its right child's value, return false

• If all left child's values are less than their right child's values, return true

Cloning a linked list-like structure

• Create a new node for each node in the original linked list

• Set the value of the new node to the value of the corresponding node in the original linked list

• Set the next pointer of the new node to the new node corresponding to the next node in the original linked list

• Repeat the above steps until all nodes in the original linked list are cloned

To find the nth character in a stream of bytes, we need to read the stream byte by byte until we reach the nth position.

• Start reading the stream byte by byte until you reach the nth position

• Return the byte at the nth position

• If the stream ends before reaching the nth position, return null or throw an exception

Rearrange a string to avoid consecutive same characters.

• Iterate through the string and keep track of the previous character.

• If the current character is the same as the previous, swap it with the next different character.

• Repeat until no consecutive same characters are left.

The task is to find the next highest palindrome number given a number.

• Convert the given number to a string

• Check if the number is already a palindrome

• If not, increment the number by 1 and check if it is a palindrome

• Repeat the previous step until a palindrome is found

Canonicalizing a directory path involves simplifying and standardizing the path to remove any redundant or unnecessary elements.

• Remove any consecutive slashes and replace them with a single slash

• Remove any trailing slashes

• Resolve any relative paths (e.g., '..' and '.')

• Handle special cases like the root directory ('/')

• Normalize the path by removing any unnecessary elements