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I applied via Recruitment Consultant and was interviewed before May 2020. There were 5 interview rounds.
Top trending discussions
It was easy
Dynamic programming questions were asked
1) convert stack to queue
2) replace special characters in a string
I applied via campus placement at National Institute of Technology (NIT), Raipur and was interviewed in Jul 2024. There were 2 interview rounds.
The coding test consists of multiple-choice questions and one medium-hard level coding question.
I applied via campus placement at Dayananda Sagar College of Engineering, Bangalore and was interviewed in Oct 2024. There were 4 interview rounds.
3 coding dsa question
Difficulty is On your luck
My friends got easy level
I got medium level
Some got hard questions as well
Ssh round , quant and logical
Tip: bring your calculator
posted on 10 Jan 2025
I applied via Referral and was interviewed before Jan 2024. There were 4 interview rounds.
Easy test, oops, logic.
posted on 8 Jan 2025
I applied via Referral and was interviewed in Dec 2024. There was 1 interview round.
posted on 8 Oct 2024
I applied via Naukri.com and was interviewed in Sep 2024. There was 1 interview round.
OOPS is a programming paradigm based on the concept of objects, which can contain data in the form of fields and code in the form of procedures.
OOPS focuses on the concept of classes and objects
Encapsulation: bundling data and methods that operate on the data within a single unit
Inheritance: allows a class to inherit properties and behavior from another class
Polymorphism: ability to present the same interface for diffe...
Comparable is an interface used for natural ordering, Comparator is an interface used for custom ordering. Abstract class can have method implementations, Interface cannot.
Comparable interface is used to define the natural ordering of objects. Example: String class implements Comparable interface for natural ordering based on alphabetical order.
Comparator interface is used to define custom ordering of objects. Example:...
Count occurrences of each character in a given string
Create an array to store the count of each character
Iterate through the string and increment the count of each character in the array
Return the array with counts for each character
Remove duplicates from an array of strings
Iterate through the array and store each element in a set to keep track of unique values
Create a new array with the unique values from the set
posted on 9 Oct 2024
based on 6 reviews
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