Write a program to return the length of the longest word from a string whose length is even.

Question

Accepted Answer

This program returns the length of the longest word from a string whose length is even.

Split the string into an array of words using a space as the delimiter.
Initialize a variable to store the length of the longest even word.
Iterate through each word in the array and check if its length is even.
If the length is even and greater than the current longest even word length, update the variable.
Finally, return the length of the longest even word.

Accepted Answer

String longestWord = Arrays.stream(sentence.split(" ")) // creates the stream with words
        .filter(s -> s.length() % 2 == 0) // filters only the even length strings
        .max(Comparator.comparingInt(String::length)) // finds the string with the max length
        .orElse(" "); // returns " " if none string is found

Accepted Answer

public int findLagrestEvenWord(String input){
return Arrays.stream(input.split("\s+")).filter(s-> s.length()%2 ==0).max(String::compareTo).get().length();
}

Accepted Answer

public class LongestEvenWord {

public static int getLongestEvenWordLength(String input) {

int longestEvenWordLength = 0;

String[] words = input.split("\s+");

for (String word : words) {

if (word.length() % 2 == 0 && word.length() > longestEvenWordLength) {

longestEvenWordLength = word.length();

}

return longestEvenWordLength;

}

public static void main(String[] args) {

String input = "The quick brown fox jumps over the lazy dog";

int longestEvenWordLength = getLongestEvenWordLength(input);

if (longestEvenWordLength == 0) {

System.out.println("There are no even-length words in the input string.");

} else {

System.out.println("The length of the longest even-length word in the input string is: " + longestEvenWordLength);

}

Write a program to return the length of the longest word from a string whose length is even.

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