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Think Future Technologies
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I applied via Internshala and was interviewed in Apr 2024. There were 3 interview rounds.
Was 1 hr with a simple question from leetcode
Reverse a linked list
Create a new linked list to store the reversed elements
Traverse the original linked list and insert each node at the beginning of the new list
Update the head of the new list as the last node of the original list
I am a dedicated and hardworking individual with relevant skills and experience for the role.
I have completed relevant coursework in the field
I have previous internship experience in a similar role
I possess strong communication and teamwork skills
Yes, I am open to relocating for the right opportunity.
I am open to relocating for the right opportunity
I am flexible and willing to move for the internship
I understand the importance of being open to relocation for career growth
I applied via Naukri.com and was interviewed in May 2024. There was 1 interview round.
I applied via Referral and was interviewed in Aug 2022. There were 2 interview rounds.
posted on 30 Nov 2022
I applied via LinkedIn and was interviewed before Nov 2021. There were 3 interview rounds.
There are basic aptitude questions for freshers level
The test was in hackerrank platform, it was moderate level.
I applied via Campus Placement
Dsa problems dp and tress problem
I am a passionate software engineer with 5 years of experience in developing web applications using various technologies.
5 years of experience in software development
Proficient in developing web applications
Skilled in using various technologies
Passionate about software engineering
I applied via Internshala and was interviewed in Sep 2022. There were 3 interview rounds.
Includes basic aptitude question with additional questions based on coding languages fundamentals.....
Binary search is a search algorithm that finds the position of a target value within a sorted array.
Divide the array into two halves
Compare the target value with the middle element
If the target value matches the middle element, return its position
If the target value is less than the middle element, search the left half of the array
If the target value is greater than the middle element, search the right half of the arra...
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