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I appeared for an interview in Apr 2022.
Round duration - 30 minutes
Round difficulty - Easy
This was just a screening round to check my intention and communication skills. They just asked me why was I looking for a job change, and told me a little bit about the profile.
Round duration - 45 Minutes
Round difficulty - Easy
Since I had applied for a full stack profile, this round mainly consisted of front-end questions and some basic DSA questions. They had scheduled a call in the afternoon around 14:00 and the call was on Google meet where I had to share my screen and type in some code, once I was happy with my code and it worked fine, I had to paste it into the google doc. Actually, they had outsourced the interview rounds to the Interview Vector.
Implement an iterator called ‘FLATTEN_2D’ to transform a two-dimensional array ‘ARR_2D’ into a one-dimensional array ‘ARR_1D’. The iterator should support the following operations...
Implement an iterator to flatten a 2D array into a 1D array in row-wise traversal.
Create a class 'FLATTEN_2D' with 'NEXT' and 'HAS_NEXT' methods.
Maintain current row and column indices to keep track of traversal.
Handle edge cases like empty rows and columns.
Combine elements row-wise to form the 1D array.
Return the elements of 'ARR_1D' for each test case.
Implement a function 'sum' with varying number of arguments to return the sum of all arguments.
Create a function 'sum' that takes in a number as argument and returns a new function that takes in the next number.
Each subsequent call to the returned function should add the argument to the running total.
Return the running total when an empty argument is passed.
Round duration - 90 Minutes
Round difficulty - Easy
This round consisted of multiple easy DSA questions, some frontend questions, and one thought experiment related to design. Again, this round was conducted around 14:00 in the afternoon.
Your task is to determine if two given strings are anagrams of each other. Two strings are considered anagrams if you can rearrange the letters of one string to form the...
Check if two strings are anagrams of each other by comparing their sorted characters.
Sort the characters of both strings and compare them.
If the sorted strings are equal, then the strings are anagrams.
Use a dictionary to count the occurrences of characters in each string for a more optimized solution.
Tip 1 : DSA is important, practice around 150+ questions minimum.
Tip 2 : For the front end, JS is a must! Learn the basics and how it works under the hood.
Tip 3 : Learn SOLID and Design patterns.
Tip 1 : Keep it short and simple. Specify your projects and/or experiences.
Tip 2 : Even naming your resume helps, instead of naming it "resume.pdf" name it like "____resume.pdf". It actually helps recruiters and I got positive feedback for this.
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I applied via Naukri.com and was interviewed in Dec 2021. There were 3 interview rounds.
I would immediately inform the project manager and the testing team about the error and work collaboratively to find a solution.
Notify the project manager and testing team about the error
Collaborate with the testing team to understand the issue
Analyze the code to identify the root cause of the error
Work with the development team to fix the error as quickly as possible
Perform thorough testing to ensure the issue is reso...
I applied via Approached by Company and was interviewed in Feb 2023. There were 3 interview rounds.
I applied via AmbitionBox and was interviewed before Sep 2020. There were 3 interview rounds.
Unique key allows null values, primary key does not.
Primary key is a unique identifier for a record in a table
Unique key allows null values, primary key does not
A table can have only one primary key, but multiple unique keys
Primary key is automatically indexed, unique key is not necessarily indexed
HAVING clause is used in SQL to filter data based on aggregate functions.
It is used with GROUP BY clause to filter data based on aggregate functions
It is used to filter data after grouping has been done
It is similar to WHERE clause but operates on grouped data
Example: SELECT department, AVG(salary) FROM employees GROUP BY department HAVING AVG(salary) > 50000;
LRU Cache is a data structure that stores the most recently used items and discards the least recently used items.
Use a hash table to store key-value pairs
Use a doubly linked list to keep track of the order of items
When an item is accessed, move it to the front of the list
When the cache is full, remove the least recently used item from the back of the list
Lookup and insertion should be O(1) time complexity
Implement 2 stacks in an array
Divide the array into two halves
Use top1 and top2 to keep track of top elements of stacks
Push and pop elements from respective halves
Check for overflow and underflow conditions
I applied via Campus Placement and was interviewed in Aug 2022. There were 3 interview rounds.
posted on 14 Mar 2023
I applied via Approached by Company and was interviewed before Mar 2022. There were 4 interview rounds.
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