Soundarapandi Suppamma Higher Secondary School PG Assistant Interview Questions and Answers

The quality of knowledge gained

Q1. How one can able to take care of gues to acquire the knowledge and numerous multiskills.
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Q2. Should acknowledge the fundamentals of a certain Topic.
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Q3. The gists of the Topic
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Q1. Q. What are abstrat class, interface?
Ans. 
Abstract class is a class that cannot be instantiated and interface is a blueprint of a class.
• Abstract class can have both abstract and non-abstract methods while interface can only have abstract methods.

• A class can implement multiple interfaces but can only inherit from one abstract class.

• Abstract class can have constructors while interface cannot.

• Example of abstract class: Animal (cannot be instantiated) and Dog (inh...read more
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Q2. Why Java does not support multiple inheritance?
Ans. 
Java does not support multiple inheritance to avoid the diamond problem and maintain simplicity.
• Multiple inheritance can lead to the diamond problem where a class inherits from two classes with a common parent.

• This can cause ambiguity and conflicts in method and variable resolution.

• Java supports multiple interface inheritance to achieve similar functionality.

• Maintaining simplicity and avoiding complexity is a core prin
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Q3. What is chained Exception?
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Chained Exception is an exception that is caused by another exception.
• It is a way of propagating exceptions through layers of code.

• It helps in identifying the root cause of an exception.

• It can be created by passing the original exception as a parameter to a new exception.

• It can be caught and handled at any level of the code.

• Example: SQLException is caused by a network error, which is caused by a firewall issue.
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Q4. What is the exception hirerchy?
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The exception hierarchy is the order in which exceptions are caught and handled in a program.
• Exceptions are caught and handled in a specific order, with more specific exceptions being caught before more general ones.

• The hierarchy typically starts with the most specific exceptions and ends with the most general ones.

• For example, in Java, the hierarchy starts with checked exceptions, followed by unchecked exceptions, and
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Aptitude test on CS subjects like C programming, DBMS, CN, and OS.

There were 2 input-output based questions of easy to moderate level

Every candidate was given an individual topic and was asked to speak on it

Q1. Some typical HR questions
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Aptitude round consists Logical reasoning, General Aptitude, Grammar related questions etc. All are moderate level questions.

Q1. Explain OOPs w.r.t Java
Ans. 
OOPs is a programming paradigm that uses objects to represent real-world entities. Java is an OOPs language.
• OOPs stands for Object-Oriented Programming System

• Java is a class-based OOPs language

• Encapsulation, Inheritance, Polymorphism, and Abstraction are the four pillars of OOPs

• Objects have state and behavior

• Java supports interfaces, which allow for multiple inheritance

• Example: A car can be represented as an object wit...read more
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Q2. Explain about the projects that you have worked on
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Q3. Explain how Java solves machine dependency of code execution
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Java solves machine dependency by using bytecode and virtual machine.
• Java code is compiled into bytecode which is platform-independent

• The bytecode is executed by the Java Virtual Machine (JVM) which is platform-specific

• JVM translates bytecode into machine code for the specific platform

• This allows Java code to run on any platform with a JVM installed

• Example: A Java program compiled on Windows can run on Linux or Mac as
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Q1. Why should we hire you?
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Q2. Tell me about yourself.
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Aptitude, reasoning, English, cloud sections

2 questions in which , one has to complete within an 50 minutes

Q1. Tell me about t Yourself
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Q2. What are the previous experiences
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Numerical ability and logical reasoning followed by some coding mcqs

Q1. Print 1 to 100 without for loop
Ans. 
Printing 1 to 100 without for loop
• Use recursion to print numbers from 1 to 99

• Print 100 outside the recursion

• Use a base case to stop recursion at 100
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