Cube of Matrix Problem Statement
Given a 2D array 'MATRIX' of size M x N, find and return the value (i * i + j * j) for those elements where the sum of the cubes of its digits equals the element itself. Here, 'i' is the row index ranging from 0 to M-1, and 'j' is the column index ranging from 0 to N-1.
Note:
If no such element exists, return -1.
Input:
The first line contains an integer ‘T’ which represents the number of test cases. Each test case consists of two lines:
The first line contains two integers ‘M’ and ‘N’ indicating the number of rows and columns, respectively.
The second line contains ‘M’ * ’N’ space-separated integers, representing the elements of the 2D array 'MATRIX'.
Output:
For each test case, output the (i * i + j * j) value for elements where the sum of the cube of its digits equals the element itself.
Note:
You are not required to print the output, it is already handled. Just implement the function.
Constraints:
- 1 <= T <= 10
- 1 <= M <= 100
- 1 <= N <= 50
- 1 <= ELEMENT <= 109
- Time limit: 1 second
AnswerBot
6d
Given a 2D array, find elements where sum of cube of digits equals element itself and return (i * i + j * j) value.
Iterate through the 2D array and check if the sum of cube of digits equals the elemen...read more
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