Open Access Technology India DOT NET Developer Interview Questions and Answers

Q1. Tell us about your experience.
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Q2. In english, give me a feedback you received lately.
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Q1. Brief explanation of SOLID principles
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Q2. Ref vs out arguments
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Aptitude,reasoning,verbal,C language,Java,C++

Q1. What is interface in JAVA
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Q2. Explain OOPS in JAVA
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Q1. Project based backend and frontend
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Q2. How to connect to backend
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To connect to the backend, you can use APIs, database connections, or web services.
• Use APIs to send and receive data between the frontend and backend

• Establish database connections to retrieve and store data

• Utilize web services for communication between different systems
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They asked from all the concepts wer have covered till now in Engineering.

Q1. Not applicable to this
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Q2. Not applicable to this one
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Q1. Dependency injection in c#
Ans. 
Dependency injection in C# is a design pattern where dependencies are injected into a class rather than the class creating them itself.
• Dependency injection helps in achieving loose coupling between classes.

• It makes the code more testable and maintainable.

• There are different ways to implement dependency injection in C#, such as constructor injection, property injection, and method injection.
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Q2. Opps related questions inheritance, polymorphism, abstract classes and interfaces
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Q3. Ooops knowledge should be perfect
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Q1. Tell me about yourself Tell me about your final year project Your family background
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Q1. Tell me about yourself Class and object Constructor Polymorphism Multithreading Exception handling
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Pattern program
Multithreading program
And overriding program

Round duration - 90 minutes
Round difficulty - Medium

Q1. 
Cycle Detection in a Singly Linked List
Determine if a given singly linked list of integers forms a cycle or not.
A cycle in a linked list occurs when a node's next points back to a previous node in the ...read more
Ans. 
The task is to determine if a given singly linked list forms a cycle or not.
• A cycle occurs when a node's next points back to a previous node in the list.

• To solve this problem, we can use the Floyd's Cycle-Finding Algorithm.

• The algorithm uses two pointers, one moving at a normal pace and the other moving twice as fast.

• If there is a cycle, the fast pointer will eventually catch up to the slow pointer.

• If the fast pointer ...read more
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Round duration - 60 minutes
Round difficulty - Medium

Q1. 
Minimum Depth of a Binary Tree
Determine the minimum depth of an integer-based binary tree. The minimum depth is defined as the number of nodes present along the shortest path from the root node down to t...read more
Ans. 
The minimum depth of a binary tree is the number of nodes along the shortest path from the root node down to the nearest leaf node.
• The minimum depth can be found by performing a breadth-first search (BFS) traversal of the binary tree

• During the BFS traversal, keep track of the current level and increment the depth by 1 for each level

• Stop the BFS traversal when a leaf node is encountered and return the depth as the minim
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Q2. 
Intersection of Two Arrays Problem Statement
Given two arrays A and B with sizes N and M respectively, both sorted in non-decreasing order, determine their intersection.
The intersection of two arrays in...read more
Ans. 
The problem is to find the intersection of two sorted arrays.
• Use two pointers to iterate through the arrays.

• Compare the elements at the current pointers and move the pointers accordingly.

• If the elements are equal, add it to the intersection array and move both pointers.

• If the element in the first array is smaller, move the first pointer.

• If the element in the second array is smaller, move the second pointer.

• Repeat until...read more
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Q3. What is the difference between a mutex and a semaphore?
Ans. 
A mutex is a binary semaphore used for mutual exclusion, while a semaphore is a generalized synchronization primitive.
• Mutex is used to protect a critical section of code, allowing only one thread to access it at a time.

• Semaphore is used to control access to a shared resource, allowing multiple threads to access it simultaneously.

• Mutex has ownership, meaning the thread that locks it must unlock it.

• Semaphore does not hav...read more
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Round duration - 60 minutes
Round difficulty - Easy

Round duration - 25 minutes
Round difficulty - Easy

Q1. Write down the recursion tree for this code:
Ans. 
Recursion tree for a given code
• Identify the base case of the recursion

• Draw a tree structure with each recursive call as a node

• Label each node with the input parameters and return values
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