There are 2 processors each executing a separate program. Processor 1: int a=10; int *ptr = &a; ptr is written into file1; processor sleeps for 10sec; printf("%d",a); Processor 2: int *p; file1 is read and contents are saved in p; *p=5; Processor 2 executes the above program when processor one is sleeping, so when printf is executed what will be the output?

Question

Accepted Answer

The output will be 5.

Processor 1 initializes variable 'a' with a value of 10 and creates a pointer 'ptr' pointing to 'a'.
Processor 1 writes the value of 'ptr' into 'file1' and then sleeps for 10 seconds.
Processor 2 reads the contents of 'file1' and saves it in pointer 'p'.
Processor 2 assigns the value 5 to the memory location pointed by 'p'.
When Processor 1 wakes up and executes the printf statement, it will print the updated value of 'a', which is 5.

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