Informatica Business Solutions Internship Trainee Interview Questions and Answers

AVL tree balance checking ensures that the tree maintains its height-balanced property after insertions and deletions.

• An AVL tree is a self-balancing binary search tree.

• The balance factor (BF) of a node is defined as the height of the left subtree minus the height of the right subtree.

• A node is considered balanced if its BF is -1, 0, or +1.

• To check balance, recursively calculate the height of left and right subtrees fo...read more

Find median of 2 sorted arrays in O(log N) time complexity and O(1) space complexity

• Use binary search to find the partition point in both arrays

• Calculate the median based on the partition point and array sizes

• Adjust the partition points based on the median value

• Repeat until the partition points are at the median

• Handle edge cases such as empty arrays and uneven array sizes

Anagram of strings in O(1) space complexity

• Use a fixed size array of integers to store the frequency of characters in the first string

• Iterate through the second string and decrement the frequency of each character in the array

• If all the frequencies are zero, then the strings are anagrams

• Return true or false accordingly

Level order traversal of a tree using Queue

• Create a queue and add the root node to it

• While the queue is not empty, remove the front node and print its value

• Add the left and right child nodes of the removed node to the queue

• Repeat until the queue is empty

Reverse level order traversal of a tree using Queue

• Create a queue and push the root node into it

• While the queue is not empty, pop the front node and push its children into the queue

• Add the popped node to a stack

• Once the queue is empty, pop elements from the stack and print them

BFS and DFS are graph traversal algorithms. BFS explores nodes level by level while DFS explores nodes depth by depth.

• BFS uses a queue while DFS uses a stack or recursion.

• BFS is optimal for finding shortest path while DFS is optimal for finding a path between two nodes.

• BFS requires more memory as it stores all the nodes at each level while DFS requires less memory.

• BFS can be used to find connected components while DFS ...read more

Check if parentheses in a string are balanced using a stack-based approach.

• Use a stack to track opening parentheses: '(', '{', '['.

• For each closing parenthesis: check if it matches the top of the stack.

• If the stack is empty at the end, parentheses are balanced.

• Example: '((){})' is balanced, but '((())' is not.

Find product of each element of an array except that element in O(N) time complexity without using / operation

• Use prefix and suffix products

• Multiply prefix and suffix products for each element to get the final product

• Handle edge cases where array has 0 or 1 element separately

Recursively delete a linked list

• Create a recursive function that takes the head of the linked list as input

• Base case: if the head is null, return

• Recursively call the function with the next node as input

• Delete the current node

Recursively delete a linked list from the end.

• Start from the head and recursively traverse to the end of the list.

• Delete the last node and set the second last node's next pointer to null.

• Repeat until the entire list is deleted.

• Use a recursive function to implement the deletion process.

Recursively delete a tree by deleting all its child nodes and then the parent node.

• Start from the leaf nodes and delete them first.

• Then move up to the parent nodes and delete them.

• Repeat until the root node is deleted.

• Use post-order traversal to ensure child nodes are deleted before parent nodes.

Recursively delete elements from the end of an array.

• Create a recursive function that removes the last element of the array.

• Call the function recursively until the desired number of elements are removed.

• Handle edge cases such as empty arrays and removing more elements than the array contains.

Floyd Warshall finds shortest path between all pairs of vertices while Djikstra finds shortest path from a single source.

• Floyd Warshall is used for dense graphs while Djikstra is used for sparse graphs.

• Floyd Warshall has a time complexity of O(n^3) while Djikstra has a time complexity of O((n+m)logn).

• Floyd Warshall can handle negative edge weights while Djikstra cannot.

• Floyd Warshall can detect negative cycles while Dj...read more

There is no known algorithm to find shortest path in 2-D space in O(log N) time.

• The best known algorithm for finding shortest path in 2-D space is Dijkstra's algorithm which has a time complexity of O(N^2).

• Other algorithms like A* and Bellman-Ford have better time complexity but still not O(log N).

• If the points are on a grid, Lee algorithm can be used which has a time complexity of O(N).

Design a system for putting newspapers using classes and functions

• Create a Newspaper class with attributes like title, date, and content

• Create a Publisher class with methods to publish and distribute newspapers

• Create a Subscriber class with methods to subscribe and receive newspapers

• Use inheritance to create different types of newspapers like daily, weekly, etc.

• Implement a database to store newspaper information and ha...read more

I believe practical experience is more valuable than higher studies.

• I have gained valuable experience through internships and projects.

• I prefer hands-on learning and problem-solving over theoretical knowledge.

• I am constantly learning and improving my skills through online courses and workshops.

My typical day as a Software Engineer involves coding, collaborating, and continuous learning to deliver high-quality software solutions.

• Morning stand-up meeting to discuss progress and blockers with the team.

• Coding sessions where I implement features or fix bugs, often using languages like Python or Java.

• Collaborating with designers and product managers to refine requirements and ensure alignment.

• Participating in code...read more

Recent issues faced in the organization include project delays, communication gaps, and technical debt impacting productivity.

• Project Delays: We encountered delays in project timelines due to unforeseen technical challenges, such as integrating legacy systems with new technologies.

• Communication Gaps: Miscommunication between teams led to misunderstandings about project requirements, resulting in rework and wasted resou...read more

Success is achieving one's goals and feeling fulfilled in the process.

• Success is subjective and varies from person to person.

• It can be achieving a personal or professional goal.

• Success can also be measured by the impact one has on others.

• Feeling fulfilled and content is a key component of success.

• Success is not always about material possessions or wealth.

Working in a corporate office fosters collaboration, enhances productivity, and provides a structured environment for professional growth.

• Collaboration: Being in a corporate office allows for face-to-face interactions, which can lead to quicker problem-solving and brainstorming sessions.

• Structured Environment: Corporate offices often provide a structured work environment with defined roles and responsibilities, which c...read more