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Cisco Summer Intern Interview Questions and Answers
Cisco Summer Intern Interview Experiences
1 interview found
Anonymous
(2 Questions)
- Q1. Nodal moving using heap at min cost
- Ans.
Nodal moving using heap at min cost involves finding the shortest path between nodes using a heap data structure.
Use Dijkstra's algorithm to find the shortest path between nodes in a graph.
Implement a min heap to efficiently store and retrieve nodes based on their cost.
Update the cost of nodes in the heap as you explore the graph to find the minimum cost path.
Example: Find the shortest path between two cities in a road...
- Q2. Array manipulation
Hard interviewer was friendly
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I applied via Referral and was interviewed before Nov 2021. There were 2 interview rounds.
(2 Questions)
- Q1. I was asked about my resume and projects as well as some of my classes I took regarding programming. I was then asked a few basic matrix algorithm questions before getting a few behavioral ones.
- Q2. How can you rotate a matrix's values?
- Ans.
To rotate a matrix's values, transpose the matrix and then reverse each row or column.
Transpose the matrix by swapping elements across the diagonal
Reverse each row or column to rotate the matrix
For clockwise rotation, reverse the rows. For anti-clockwise, reverse the columns
Example: [[1,2,3],[4,5,6],[7,8,9]] -> [[1,4,7],[2,5,8],[3,6,9]] -> [[7,4,1],[8,5,2],[9,6,3]]
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I applied via Referral and was interviewed before Nov 2021. There were 2 interview rounds.
(2 Questions)
- Q1. I was asked about my resume and projects as well as some of my classes I took regarding programming. I was then asked a few basic matrix algorithm questions before getting a few behavioral ones.
- Q2. How can you rotate a matrix's values?
- Ans.
To rotate a matrix's values, transpose the matrix and then reverse each row or column.
Transpose the matrix by swapping elements across the diagonal
Reverse each row or column to rotate the matrix
For clockwise rotation, reverse the rows. For anti-clockwise, reverse the columns
Example: [[1,2,3],[4,5,6],[7,8,9]] -> [[1,4,7],[2,5,8],[3,6,9]] -> [[7,4,1],[8,5,2],[9,6,3]]
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