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Ojas Innovative Technologies
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I applied via Walk-in and was interviewed before Nov 2022. There were 2 interview rounds.
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I applied via Approached by Company and was interviewed in Sep 2021. There were 2 interview rounds.
I applied via Approached by Company and was interviewed in Nov 2024. There was 1 interview round.
Sql question more and related to database
I applied via Naukri.com and was interviewed before Nov 2021. There were 2 interview rounds.
posted on 15 Jul 2022
I applied via Referral and was interviewed before Jul 2021. There were 3 interview rounds.
If you are a fresher , then this is for you else almost no coding test for experienced candidates.
I applied via Approached by Company and was interviewed in Oct 2022. There were 4 interview rounds.
Good Process of interview was a great experience
I appeared for an interview before Oct 2023.
Good Knowledge of DSA is required
I add value to the company by leveraging my skills and experience to drive growth, improve efficiency, and enhance overall performance.
Implementing cost-saving initiatives
Developing innovative solutions to challenges
Improving processes and workflows
Increasing revenue through strategic partnerships
Enhancing customer satisfaction and retention
I applied via Referral and was interviewed in Jul 2023. There were 2 interview rounds.
I applied via Referral and was interviewed before Feb 2022. There were 4 interview rounds.
Easy level questions on string, linked list and array
TCP is a connection-oriented protocol while UDP is connectionless.
TCP provides reliable, ordered, and error-checked delivery of data while UDP does not guarantee any of these.
TCP is slower but more reliable while UDP is faster but less reliable.
TCP is used for applications that require high reliability and accuracy such as email, file transfer, and web browsing while UDP is used for applications that require speed and ...
A nibble swap program in C
Nibble swap means swapping the 4-bit halves of a byte
Use bitwise operators to perform the swap
Example: unsigned char x = 0xAB; x = ((x & 0x0F) << 4) | ((x & 0xF0) >> 4);
Reverse a linked list in C language.
Create three pointers: current, previous, and next.
Traverse the linked list and change the direction of the pointers.
Return the new head of the reversed linked list.
API call in C
Include the necessary header files
Create a URL string with the required parameters
Use the curl library to make the API call
Handle the response data appropriately
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