Process p1 & p2. p1 writes to an address & sleeps...p2 writes another value to the same address & terminates. Now p1 wakes up & reads value of that address. He asked me the output.What is Role of OS in this
AnswerBot
1y
The output of p1 depends on the synchronization mechanism used by the operating system.
If the OS uses a lock or semaphore to synchronize access to the shared address, p1 will read the value written by...read more
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