Elektrobit India Engineer Trainee Interview Questions and Answers

Q1. Related to fpga qutioms
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Q2. Ask About protocols and implementation
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Asked Basic Aptitude Questions

Q1. Nmos Cross Section drawing
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Q2. Asic design flow
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Q3. Asic vs fpga difference
Ans. 
ASICs are custom-designed for specific applications, while FPGAs are reprogrammable and more flexible.
• ASICs are Application-Specific Integrated Circuits designed for a specific purpose or application.

• FPGAs are Field-Programmable Gate Arrays that can be reconfigured for different tasks.

• ASICs are more efficient and faster than FPGAs for specific tasks.

• FPGAs are more flexible and can be reprogrammed for different function...read more
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Q4. Static Timing Analysis
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Q5. Projects related (verilog)
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4 Questions- 90 minutes
Medium to Hard level questions.
I solved 2.5 questions in 70 minutes and submitted the test because i was sure that the remaining 20 minutes wont help me.

Q1. Easy questions. Basic programming. SQL. Resume based.
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Q1. Friendly Round. Basic discussion Communication check
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Round duration - 90 minutes
Round difficulty - Easy

Timing - 10AM-11:30AM
Online proctored test

Q1. 
Binary Tree Right View Problem Statement
Given a binary tree of integers, your task is to print the right view of it. The right view represents a set of nodes visible when the tree is viewed from the righ...read more
Ans. 
The task is to print the right view of a binary tree, representing nodes visible from the right side in top-to-bottom order.
• Traverse the tree level by level and keep track of the rightmost node at each level

• Print the rightmost node of each level to get the right view of the tree

• Use a queue for level order traversal and a map to store the rightmost nodes
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Q2. 
0/1 Knapsack Problem Statement
A thief is planning to rob a store and can carry a maximum weight of 'W' in his knapsack. The store contains 'N' items where the ith item has a weight of 'wi' and a value of...read more
Ans. 
Yes, the 0/1 Knapsack problem can be solved using dynamic programming with a space complexity of not more than O(W).
• Use a 1D array to store the maximum value that can be stolen for each weight from 0 to W.

• Iterate through each item and update the array based on whether including the item would increase the total value.

• The final value in the array at index W will be the maximum value that can be stolen.
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Round duration - 45 minutes
Round difficulty - Medium

Timing : 4PM-5PM
Environment - Online

There was a panel of 3 interviewers

Q1. How can you find the size of an array in C or C++ without using sizeof or any standard function?
Ans. 
You can find the size of an array in C or C++ by dividing the total size of the array by the size of one element.
• Calculate the total size of the array by multiplying the number of elements by the size of each element.

• Divide the total size by the size of one element to get the size of the array.

• For example, if you have an array of strings arr[] = {'hello', 'world', 'example'}, you can find the size by dividing the total
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Q2. Explain how indexing in a database works using B+ trees.
Ans. 
B+ trees are used for indexing in databases to efficiently search and retrieve data.
• B+ trees are balanced trees where each node can have multiple keys and child pointers.

• Data is stored in leaf nodes, while non-leaf nodes are used for navigation.

• B+ trees are commonly used in databases because of their ability to efficiently search and retrieve data.

• Example: In a database table with an index on a specific column, B+ tree...read more
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Round duration - 45 mintues
Round difficulty - Easy

Timing - 11AM-12:15PM
Environment - online video call

Again there was a panel of 2 senior engineers

Q1. 
Maximum Path Sum Problem Statement
You are given an n-ary tree consisting of 'N' nodes. Your task is to determine the maximum sum of the path from the root to any leaf node.
Example:
Input:
For the giv...read more
Ans. 
Find the maximum sum of the path from the root to any leaf node in an n-ary tree.
• Traverse the tree from root to leaf nodes while keeping track of the sum of each path.

• At each node, calculate the sum of the path from the root to that node and update the maximum sum found so far.

• Consider using depth-first search (DFS) or breadth-first search (BFS) for tree traversal.

• Handle cases where nodes have negative values or where
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