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I applied via Approached by Company and was interviewed in Aug 2024. There was 1 interview round.
2 problem was given to solve
1) Smallest Negative balance - -----%20America%20-%20Weekly%20Algorithm%20Challenges/Week%2021%20Algorithm%20Challenge/Smallest%20Negative%20Balance.md
2) Find the absolute difference between alpha & beta from the array.
Alpha -An element k in a array occurs k consecutive time
Beta - An element k in an array occurs k consecutive time starting from index k
Sample input
Arr[] = {2,2,2,4,4,4,4,1,2,2]
Output
Alpha - 3
Beta - 1
Absolute difference - 1
Note : consider array index starts with 1
I applied via Campus Placement and was interviewed in Aug 2024. There were 2 interview rounds.
50 questions were given and we were supposed to solve it in 45 mins. But from what I've heard only 12 students made it to the next round.
Didn't qualify but it consisted of leetcode medium-hard questions.
I applied via Campus Placement and was interviewed in Aug 2024. There were 3 interview rounds.
MCQ on computer fundamentals
5 DSA questions medium , hard lvl
Duration is 45 minutes
Data structures and java programming
posted on 21 Oct 2023
I applied via Campus Placement and was interviewed in Sep 2023. There were 3 interview rounds.
50 questions should be answered in 45 minutes. They include Aptitude, OS, Pseudo codes, micro processors etc
5 questions will be given 1 easy 2 med 2 hard. Atleast 3 and more should be done
JS is used for web development due to its compatibility with browsers, asynchronous capabilities, and large community support.
JavaScript is the only language that can be executed in the browser, making it essential for client-side scripting.
JS has asynchronous capabilities, allowing for non-blocking operations which are crucial for web development.
There is a large community of developers using JS for web development, p...
Basics computer fundamentals questions like oops dsa dbms sql
5 coding questions , 2 are easy 3 medium
Event bubbling is the propagation of an event from the innermost child element to the outermost parent element.
Events triggered on a child element will also trigger on its parent elements
The event travels up the DOM tree until it reaches the document object
Can be stopped using event.stopPropagation()
Can be useful for event delegation
The .on('click',function() is a more flexible method than .click(function())
The .on() method can handle multiple events and selectors
The .click() method can only handle one event and one selector
The .on() method can also handle dynamically added elements
The .click() method cannot handle dynamically added elements
Function to check if two strings are anagram or not
Create two character arrays from the strings
Sort the arrays
Compare the sorted arrays
Function to determine the order of integers in an array.
Check first and last element to determine if increasing or decreasing
Check for inflection point to determine if order changes
Return order type as string
Optimize images, minify code, reduce HTTP requests, use caching, and lazy loading.
Optimize images using compression and appropriate file formats
Minify code to reduce file size and improve load times
Reduce HTTP requests by combining files and using sprites
Use caching to store frequently accessed data locally
Implement lazy loading to defer loading of non-critical resources
Design a database schema for a movie site with user ratings and recommendations.
Create tables for movies, users, ratings, and recommendations
Use foreign keys to link tables
Include columns for movie genre and user watch history
Algorithm for recommendations can use user watch history and ratings to suggest similar movies
Function to simulate dice roll with equal probability without using random function
Use a toss function that returns either 0 or 1 with equal probability
Call the toss function 3 times and convert the result to a binary number
If the binary number is greater than 0 and less than or equal to 6, return it
If the binary number is greater than 6, repeat the process
Query to fetch duplicate email from table
Use GROUP BY and HAVING clause to filter out duplicates
SELECT email, COUNT(*) FROM table_name GROUP BY email HAVING COUNT(*) > 1;
This will return all the duplicate emails in the table
I applied via Campus Placement
I applied via Referral
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