How will you print the address of a variable without using a pointer?

Question

Accepted Answer

You can print the address of a variable without using a pointer by using the & operator in C/C++.

Use the & operator before the variable name to get its address, e.g. int num = 10; printf("Address of num: %p", &num);
You can also pass the variable directly to a function that expects a pointer, e.g. void printAddress(int *ptr) { printf("Address: %p", ptr); } int num = 20; printAddress(&num);

Accepted Answer

#include <stdio.h>
int main(void)
{
   // declaring the variables 
   int x;
   float y;
   char z;
   printf("Address of x: %p
", &x);
   printf("Address of y: %p
", &y);
   printf("Address of z: %p
", &z);
   return 0;
}

How will you print the address of a variable without using a pointer?

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