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I applied via LinkedIn and was interviewed before Oct 2022. There were 3 interview rounds.
Basic and easy aptitude questions
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I applied via Campus Placement
Basic aptitude , c programming, digital design
Flip flop can be implemented using a multiplexer by selecting the input based on the control signal.
Use a 2:1 multiplexer to select between the current state and the next state
Connect the output of the multiplexer to the input of the flip flop
Control signal determines which input is passed through the multiplexer
posted on 13 Nov 2024
Easy - Medium Leetcode
A ridesharing service connecting drivers with passengers for convenient and affordable transportation.
Allow users to request rides through a mobile app
Match drivers with passengers based on location and destination
Provide estimated arrival times and fare estimates
Implement a rating system for drivers and passengers
Offer options for shared rides to reduce costs
I applied via Campus Placement
Basic aptitude , c programming, digital design
Flip flop can be implemented using a multiplexer by selecting the input based on the control signal.
Use a 2:1 multiplexer to select between the current state and the next state
Connect the output of the multiplexer to the input of the flip flop
Control signal determines which input is passed through the multiplexer
I was interviewed in Sep 2021.
Round duration - 60 minutes
Round difficulty - Medium
The round was technical round and it was held on google meet around 1 pm
In this approach, we'll try to consider each rectangle that can be formed using elements of the array. To do this we fix (X1,Y1) coordinates of starting vertex and iterate through the matrix for every pair (X2,Y2) as the coordinates of ending vertex. Now we have a rectangle with coordinates (X1,Y1), (X1,Y2), (X2,Y1) and (X2,Y2).
We'll find the sum of elements within this rectangle and compare it with MAXSUM. ...
Round duration - 60 minutes
Round difficulty - Medium
It was managerial round and took place around 3 pm
We will scan the expression from left to write and if we encounter an operand we will append it to our answer. If we encounter an operator we will pop all the operators with equal or higher precedence and append them to our answer. And push the current operator. In the end, we will empty the stack.
Order of precedence = [ ‘^’, ‘*’ and ‘/’, ‘+’ and ‘-’, ‘(’, ‘)’]
Order of precedence [ link ]
The algorithm will be-
Tip 1 : Java concepts should be strong
Tip 2 : OOPS
Tip 3 : Projects should have scalability
Tip 1 : Projects detail should be short and precise
Tip 2 : Don't fake technical skills
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