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Aptitude
A motorist covers a distance of 39km in 45min by moving at a speed of x kmph for the first 15min, then moving at double the speed for the next 20 min, and then again moving at his original speed for the rest of the journey. Find x.?
36km/hr.
35km/hr.
37km/hr.
34km/hr.
Answer : 1.Total distance = 39 km Total time = 45 min D = S*T `x * 15/60 + 2x * 20/60 + x * 10/60 = 39 km `x = 36 kmph
A & B are two towns. A person covers the distance from A to B on cycle at 17kmph and returns to A by a boat running at a uniform speed of 8kmph. His average speed for the whole journey is?
10.88kmph.
10.99kmph.
10kmph.
12.33kmph.
Answer : 1.When same distance is covered with different speeds, then the average speed = `(2 * x * y) / (x + y)` = 10.88kmph
A car covers 4 successive 3km stretches at speed of 10kmph, 20kmph, 30kmph & 60kmph resp. Its average speed is?
20kmph.
30kmph.
25kmph.
27kmph.
Average speed = total distance / total time total distance = 4 * 3 = 12 km total time = `3/10 + 3/20 + 3/30 + 3/60` = `36/60` hr speed =`12/(36 / 60)` = 20 kmph
if it takes 60 seconds to complete one round around the clock what would be the time required to complete 1200 rounds of the same clock
1200 minutes
3 hours
42000 secs
45000 secs
1 round takes 60 seconds.
1200 rounds will take ? seconds.
? = 1200 * 60 seconds = 72000 seconds.
Not in option. So we check for minutes.
`(1200 * 60) / 60 = 1200 min`
Find the odd number:
2,3,5,19,25,31,37
5
25
19
31
Except 25 all other are prime numbers.
1,1,2,3,3,4,5,9,8
9
8
2
3
Sum of Alternate number gives next alternate number.
1+2=3;2+3=5;3+5=8;
1+3=4;3+4=7;
7 is the correct number in sequence not 9
January 1, 1992 was a Wednesday. What day of the week will it be on January 1, 1993 ?
Monday
Friday
Tuesday
Sunday
1992 being a leap year, it has 2 odd days. So, the first day of the year 1993 will be two days beyond Wednesday. ie it will be Friday
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