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Aptitude
If birthday of Raj was celebrated on 5th January, Tuesday 1993 what would be the day when he celebrates his 21st birthday?
Saturday
Sunday
Thursday
Wednesday
5th Jan 1993 is Tuesday
1993+21=2014
He will celebrate his 21st birthday on 5th Jan 2014.
Number of leap years: 5 (1996,2000,2004,2008,2012)
Number of non-leap years: 16
We add 2 days for a leap year and 1 day for non-leap years.
Therefore (2*5)+16 = 26
A day repeats itself in 7 days. Therefore, we do 26/7 whose remainder is 5 days.
Add 5 days after Tuesday.
Tuesday + 5 = Sunday.
Answer: Sunday
Today is 29th November,2015 is a sunday. What would be 364th day from now?
Monday
Friday
Today is 29th November, 2015 falls on Sunday.
Now 2016 is a leap year. February will have 29 days.That is a year from 29th November 2015 to 29th November 2016 will have 366 days.
Therefore, after 364 days, the day will be 27th November, 2016.
Therefore, if 29th November 2015 is Sunday,then, 29th November 2016 will Tuesday. (As for a leap year, we add two days)
Therefore, the day on 27th November 2016 will be Sunday.
What would be the person's age after 180 months if his current age is 28 years?
43 years
42 years
41 years
40 years
There are 12 months in a year. Hence, 180 months is 15 years. If the person's current age is 28 years, then his age after 15 years would be 43 years which is the required answer.
What is 12 percent of 80 percent of 50?
5
6
4.8
3.6
12% of 80% of 50
= 12% of `(80/100 ** 50)`
= 12% of 40
= `12/100 ** 40`
= 4.8
A person walks at 5kmph for 6hr and at 4km/h for 12hr. His average speed is ?
`4 1/3` km/h
8km/hr
`8 1/4`km/hr
9 km/hr
Answer : 1.`"Avg speed" = "total distance"/"total time"`= `((5*6) + (4*12)) / 18`=`4 1/3` km/h
A man can cover a distance in 1hr 24min by covering 2/3 of the distance at 4 km/h and the rest at 5km/h. The total distance is
4km
6.5km
9km
6km
Answer : 4
Total time = 1hr 24min = 60min + 24 min = 84 min = `84/60`hoursLet total distance be S.
`"Time" = "Distance" / "Speed"`
`84/64 = ((2S)/3)/4 + (S/3)/5`
`84/64 = (S/6) + (S/15)`
`84/64 = (21S)/(6*15)`
`S = (84 * 6 * 15)/(64 * 21)`
S = 6km
In covering a distance of 30 km, A takes 2 hours more than B. If A doubles his speed, then he would take 1 hour less than B. A's speed is:
5 1/4km/hr
5km/hr
6km/hr
Walking at the rate of 4kmph a man cover certain distance in 2hr 45 min. Running at a speed of 16.5 kmph the man will cover the same distance in.
39min.
47min.
40min.
41min.
Answer : 3.
Time= 2hr 45min = `2 45/60 hr = 2 3/4 hr = 11/4 hr`Distance = Speed * time`4*11/4 = 11km`New Speed = 16.5 kmphTherefore `"time" = "Distance"/"Speed" = 11/16.5 = 40min`
Two monkeys starting from the same place walk at a rate of 5kmph and 5.5kmph respectively. What time will they take to be 8.5km apart, if they walk in the same direction?
17hrs.
18hrs.
17 1/30hrs.
16hrs.
Answer : 1.The relative speed of the boys = 5.5kmph – 5kmph= 0.5 kmphDistance between them is 8.5 kmTime= `"8.5km"/"0.5 kmph" = 17 hrs`
A man covers a distance on scooter. Had he moved 3kmph faster he would have taken 40 min less. If he had moved 2kmph slower, he would have taken 40min more. The distance is?
40km.
41km.
35km.
39km.
Answer : 1.Let distance = x m Usual rate = y kmph `x/y – x/(y+3) = 40/60 hr` 2y(y+3) = 9x ---------------------------------(1)
`x/(y-2) – x/y = 40/60 hr` y(y-2) = 3x -----------(2)
divide 1 & 2 equations by solving we get x = 40 km
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