Technician Supervisor

Technician Supervisor Interview Questions and Answers

Updated 11 Oct 2020

Q1. Why basic knowledge of components required in repairing in electronics instruments?

Ans.

Basic knowledge of components is necessary for effective repair of electronics instruments.

  • Understanding the function of each component helps in identifying faulty parts.

  • Knowledge of components helps in selecting the right tools and techniques for repair.

  • Components may need to be replaced or repaired, and knowledge of their specifications is important.

  • Examples of components include resistors, capacitors, transistors, and diodes.

Q2. What is the difference between AC and DC?

Ans.

AC stands for Alternating Current and DC stands for Direct Current. AC changes direction periodically while DC flows in one direction.

  • AC is used in household appliances and power grids while DC is used in batteries and electronic devices.

  • AC voltage can be easily changed using a transformer while DC voltage cannot be changed easily.

  • AC is more dangerous than DC because it can cause muscle contractions and heart fibrillation.

  • DC is more efficient than AC for long-distance power t...read more

Q3. What are the basic electronics components?

Ans.

Basic electronics components include resistors, capacitors, inductors, diodes, transistors, and integrated circuits.

  • Resistors: used to limit current flow

  • Capacitors: used to store and release electrical energy

  • Inductors: used to store energy in a magnetic field

  • Diodes: used to allow current flow in one direction

  • Transistors: used to amplify or switch electronic signals

  • Integrated circuits: contain multiple components on a single chip

Q4. How to place Capacitor in series or parallel?

Ans.

Capacitors can be placed in series or parallel depending on the desired capacitance and voltage rating.

  • In series, the capacitance decreases while the voltage rating increases.

  • In parallel, the capacitance increases while the voltage rating stays the same.

  • When placing capacitors in series, the total capacitance is calculated as 1/Ctotal = 1/C1 + 1/C2 + ...

  • When placing capacitors in parallel, the total capacitance is calculated as Ctotal = C1 + C2 + ...

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