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I applied via Naukri.com and was interviewed in Nov 2021. There was 1 interview round.
I applied via Naukri.com and was interviewed in Oct 2023. There were 3 interview rounds.
Small task in catia api
Singularity in BIW refers to a point where multiple body panels meet in a vehicle's body structure.
Singularity is a critical point in BIW design where multiple panels converge.
It is important to ensure proper fit and alignment at singularity points to maintain structural integrity.
Examples of singularity points include door openings, roof joints, and hood connections.
The time taken for spot welding by a robot depends on various factors such as material thickness, type of material, welding parameters, and robot speed.
Time taken for spot welding can vary based on the material thickness. Thicker materials may require longer welding times.
The type of material being welded can also impact the time taken. Different materials have different conductivity and heat transfer properties.
Weldin...
posted on 5 Jul 2022
I applied via Company Website and was interviewed before Jul 2021. There were 3 interview rounds.
Quant, Technical and Logical Reasoning
OWASP Top 10 is a list of the most critical web application security risks.
It is updated every 3-4 years by the Open Web Application Security Project (OWASP)
The list includes vulnerabilities such as injection, broken authentication and session management, cross-site scripting (XSS), and more
It is used as a guide for developers and security professionals to prioritize their security efforts
The latest version is OWASP To
Scenario based case study, to identify risk based observations
posted on 27 Sep 2022
I applied via Company Website and was interviewed before Sep 2021. There were 3 interview rounds.
posted on 21 Jul 2024
A pointer to pointer is a variable that stores the memory address of another pointer variable.
It is used to create dynamic data structures like linked lists and trees.
It allows multiple levels of indirection.
It is denoted by ** in C and C++.
Example: int **ptr;
Example: ptr = &p; where p is a pointer variable.
I appeared for an interview in Jan 2022.
Round duration - 90 minutes
Round difficulty - Medium
Determine if a given singly linked list of integers forms a cycle or not.
A cycle in a linked list occurs when a node's next
points back to a previous node in the ...
The task is to determine if a given singly linked list forms a cycle or not.
A cycle occurs when a node's next points back to a previous node in the list.
To solve this problem, we can use the Floyd's Cycle-Finding Algorithm.
The algorithm uses two pointers, one moving at a normal pace and the other moving twice as fast.
If there is a cycle, the fast pointer will eventually catch up to the slow pointer.
If the fast pointer ...
Round duration - 60 minutes
Round difficulty - Medium
Determine the minimum depth of an integer-based binary tree. The minimum depth is defined as the number of nodes present along the shortest path from the root node down to t...
The minimum depth of a binary tree is the number of nodes along the shortest path from the root node down to the nearest leaf node.
The minimum depth can be found by performing a breadth-first search (BFS) traversal of the binary tree
During the BFS traversal, keep track of the current level and increment the depth by 1 for each level
Stop the BFS traversal when a leaf node is encountered and return the depth as the minim
Given two arrays A
and B
with sizes N
and M
respectively, both sorted in non-decreasing order, determine their intersection.
The intersection of two arrays in...
The problem is to find the intersection of two sorted arrays.
Use two pointers to iterate through the arrays.
Compare the elements at the current pointers and move the pointers accordingly.
If the elements are equal, add it to the intersection array and move both pointers.
If the element in the first array is smaller, move the first pointer.
If the element in the second array is smaller, move the second pointer.
Repeat until...
A mutex is a binary semaphore used for mutual exclusion, while a semaphore is a generalized synchronization primitive.
Mutex is used to protect a critical section of code, allowing only one thread to access it at a time.
Semaphore is used to control access to a shared resource, allowing multiple threads to access it simultaneously.
Mutex has ownership, meaning the thread that locks it must unlock it.
Semaphore does not hav...
Round duration - 60 minutes
Round difficulty - Easy
Round duration - 25 minutes
Round difficulty - Easy
Tip 1 : Practice a lot of DSA questions on various online platforms.
Tip 2 : Regularly go back to some of the typical DSA questions.
Tip 3 : Give equal importance to OS, OOPS, and CN subjects.
Tip 1 : Be thorough with your resume to answer anything and everything from your resume.
Tip 2 : Do not put false information on your resume.
I applied via Recruitment Consulltant and was interviewed before Oct 2022. There were 5 interview rounds.
Technical interview on different types of routing paths
based on 1 review
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