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I applied via Campus Placement and was interviewed in Mar 2024. There were 2 interview rounds.
Use XOR operation to swap two numbers without extra space
Use XOR operation to swap two numbers without using extra space
Example: a = 5, b = 7. a = a XOR b, b = a XOR b, a = a XOR b. Now a = 7, b = 5
Find the Duplicate number
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I was interviewed before May 2016.
I applied via Naukri.com and was interviewed before Jun 2020. There were 5 interview rounds.
I applied via Campus Placement and was interviewed before Sep 2021. There were 4 interview rounds.
Math and verbal round .
General topics to speak
Implement a function to find duplicates in an array of strings using Hashmap.
Create a Hashmap to store the frequency of each string in the array
Iterate through the array and check if the frequency of any string is greater than 1
If yes, add it to the list of duplicates
Return the list of duplicates
I was interviewed in Mar 2017.
To make the red fishes 98%, 50 fishes have to be removed from the aquarium.
Calculate 1% of 200 fishes to find the number of red fishes.
Subtract the number of red fishes from 200 to find the number of non-red fishes.
Calculate 2% of the total number of fishes to find the desired number of red fishes.
Subtract the desired number of red fishes from the current number of red fishes to find the number of fishes to be removed.
posted on 28 Jun 2017
I was interviewed in Mar 2017.
To make the red fishes 98%, 50 fishes have to be removed from the aquarium.
Calculate 1% of 200 fishes to find out how many fishes represent 1%.
Multiply the result by 2 to find out how many fishes represent 2%.
Subtract the result from 200 to find out how many fishes represent 98%.
I was interviewed in Feb 2017.
posted on 3 May 2017
I was interviewed before May 2016.
I was interviewed in Mar 2017.
To make the red fishes 98%, 50 fishes have to be removed from the aquarium.
Calculate 1% of 200 fishes, which is 2 fishes.
To make the red fishes 98%, subtract 1% (2 fishes) from 99% (198 fishes).
To find the number of fishes to be removed, divide the difference by 1% (2 fishes).
Therefore, 50 fishes have to be removed to make the red fishes 98%.
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