Given 2 game scenarios for basketball, and given p as the probability of making a basket in an attempt, I have to understand the condition where game1 would be preferable over game2. In first game, I have one trial and have to make a basket in that trial to win. In second game, I am given 3 trials and have to make at least 2 baskets to win

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Comparing 2 basketball game scenarios with different number of trials and baskets required to win

Calculate the probability of winning in each game scenario using binomial distribution formula
Compare the probabilities to determine which game scenario is preferable
In game1, the probability of winning is p. In game2, the probability of winning is the sum of probabilities of making 2 or 3 baskets
If p is high, game1 is preferable. If p is low, game2 is preferable
For example, if p = 0.6, the probability of winning in game1 is 0.6 and in game2 is 0.684

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