public static void getsum(int a,int b){System.out.println("a b method");}public static void getsum(int a,int b,int c){System.out.println("a b c method");}public static void getsum(int a,int ...b){System.out.print("a...b method")

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Accepted Answer

The question is about method overloading in Java.

Method overloading allows multiple methods with the same name but different parameters.
The method to be called is determined at compile-time based on the arguments passed.
In the given code, there are three overloaded methods with the same name 'getsum'.
The first method takes two integers as arguments.
The second method takes three integers as arguments.
The third method takes one integer followed by a variable number of integers as arguments.

public static void getsum(int a,int b){System.out.println("a b method");}public static void getsum(int a,int b,int c){System.out.println("a b c method");}public static void getsum(int a,int ...b){System.out.print("a...b method")

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