Given a maximum of 100 digit numbers as input, find the difference between the sum of odd and even position digits

Question

Accepted Answer

Find the difference between the sum of odd and even position digits in a maximum of 100 digit number.

Iterate through the digits of the number and add the digits at odd positions to a variable for odd position digits and even positions to a variable for even position digits.
Calculate the difference between the two variables.
Return the difference.
Example: For the number 123456, the sum of digits at odd positions is 1+3+5=9 and the sum of digits at even positions is 2+4+6=12. The difference is 12-9=3.

Accepted Answer

#include 
 #include 
 #include 
 
 int main()
 {
  int a = 0,b = 0,i = 0, n;
  char num[100];
  
  printf("Enter the number:");
  scanf("%s",num); //get the input up to 100 digit
  n = strlen(num);
  while(n>0)
  {
  if(i==0) //add even digits when no of digit is even and vise versa
  {
  a+=num[n-1]-48;
  n--;
  i=1;
  }
  else //add odd digits when no of digit is even and vice versa
  {
  b+=num[n-1]-48;
  n--;
  i=0;
  }
  }
  printf("%d",abs(a-b)); //print the difference of odd and even
 
  return 0;
 }

Given a maximum of 100 digit numbers as input, find the difference between the sum of odd and even position digits

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