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posted on 28 Aug 2021
I applied via Company Website and was interviewed before Aug 2020. There was 1 interview round.
posted on 3 Dec 2015
Finding an element in a rotated array
Identify the pivot point where the array is rotated
Divide the array into two sub-arrays based on the pivot point
Perform binary search on the appropriate sub-array to find the element
Handle edge cases like when the element is at the pivot point
Create a linked list that contains the sum of two given linked lists representing numbers.
Traverse both linked lists simultaneously and add the corresponding nodes' values. If the sum is greater than 9, carry over the 1 to the next node.
If one linked list is longer than the other, add the remaining nodes to the sum.
Create a new linked list with the sum in reverse order.
Given a binary search tree, print the path with sum k and minimum hops.
Traverse the tree using DFS and keep track of the current path and its sum.
If the current sum equals k, compare the current path with the minimum path found so far.
If the current sum is greater than k, backtrack to the previous node and continue traversal.
If the current sum is less than k, continue traversal.
Return the minimum path found.
Time comple...
posted on 9 Oct 2020
posted on 17 Dec 2022
They ask us 40 mcqs and 2 coding questions. Mcqs are from networking,OS,DS,Ada and also have questions of general aptitude like direction,blood relation. Coding question are not easy both the questions are from Graph.
Find unique character from a string and optimize it
Use a hash table to store the frequency of each character in the string
Iterate through the hash table to find the character with frequency 1
If there are multiple characters with frequency 1, return the first one
Optimization: Stop iterating through the hash table once a character with frequency 1 is found
They give me a scenario like you have to go from place A to place B then what should You consider.
posted on 1 Nov 2022
I was interviewed in May 2022.
BST search time is O(log n) on average, but can be O(n) in worst case.
BST search time depends on the height of the tree
On average, height is log base 2 of n
Worst case is when the tree is unbalanced and height is n
Example: searching for a value in a balanced BST with 1024 nodes takes at most 10 comparisons
posted on 8 Apr 2022
I applied via LinkedIn and was interviewed in Mar 2022. There were 2 interview rounds.
Kubernetes cluster can be exposed to the internet using various methods.
One way is to use a LoadBalancer service type to expose the cluster to the internet.
Another way is to use an Ingress controller to route traffic from the internet to the cluster.
A third way is to use a NodePort service type to expose the cluster to the internet.
It is important to secure the cluster by using authentication and authorization mechanis...
Ingress is a Kubernetes resource that manages external access to services. Prometheus is a monitoring system and Grafana is a visualization tool.
Ingress is used to route external traffic to the appropriate Kubernetes service
Prometheus is used to collect and store metrics from various sources
Grafana is used to visualize the collected metrics in a user-friendly way
Ingress can be configured to use different load balancing...
I applied via Referral and was interviewed in Feb 2022. There were 3 interview rounds.
posted on 21 Dec 2022
Explanation of linked list reversal and RabbitMQ
Linked list reversal can be done iteratively or recursively
Iterative reversal involves changing the pointers of each node to point to the previous node
Recursive reversal involves calling the function recursively on the next node and changing its pointer to the current node
RabbitMQ is a message broker that allows for asynchronous communication between applications
It uses a...
posted on 2 Jan 2023
I applied via Campus Placement and was interviewed in Jul 2022. There were 3 interview rounds.
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