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I applied via Campus Placement and was interviewed in Sep 2023. There were 4 interview rounds.
It's contains verbal , quantitative questions.
3 coding questions will be given
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I appeared for an interview in Feb 2024.
Single responsibility principle states that a class should have only one reason to change.
Each class should have only one responsibility
Helps in making code more maintainable and easier to understand
Promotes separation of concerns
Example: A class that handles user authentication should not also handle file management
posted on 10 Sep 2023
It was an easy test. It consisted of MCQs and two coding qns. Prepare SQL well. It also had 2 programming question. Both were medium difficukty
I applied via Company Website and was interviewed in May 2021. There were 5 interview rounds.
First round was aptitude with coding round it was easy
1st round was DSA round. Pretty easy
Currying is a technique in functional programming where a function with multiple arguments is transformed into a sequence of nested functions, each taking a single argument.
Currying can be achieved using arrow functions in JavaScript.
Arrow functions automatically bind 'this' and do not have their own 'this' value.
Example: const add = a => b => a + b;
Example: const addFive = add(5); const result = addFive(3); // result
3 questions 3 sum linked list missing sum
System design involves creating a high-level architecture of a software system, while HR principles focus on managing people effectively.
System design involves identifying components, defining their interactions, and ensuring scalability and reliability.
HR principles include hiring the right talent, providing training and development opportunities, and fostering a positive work culture.
Both system design and HR princip...
I applied via Campus Placement and was interviewed in Oct 2024. There were 2 interview rounds.
Loop in linked list is a situation where a node points to a previous node in the list, creating an infinite loop.
Check for loops using Floyd's cycle detection algorithm
Use two pointers, one moving twice as fast as the other, to detect a loop
If the fast pointer catches up to the slow pointer, there is a loop
Two coding questions, one is easy and the other is difficult. Who solved 2nd question was shortlisted for an interview.
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