Sorting Characters by Frequency
Given a string S
, sort this string in increasing order based on the frequency of its characters. If two characters have the same frequency, the character with a lesser ASCII value should appear first. Return the sorted string following these conditions.
Input:
The first line contains a single integer ‘T’ representing the number of test cases. The first line of each test case contains a single integer ‘N’ denoting the length of the string ‘S’. The next line of the test case contains the string ‘S’.
Output:
For each test case, print the sorted string.
Example:
Input: S= “abAb” Output: “Aabb” Explanation: ‘a’ and ‘A’ have frequency 1 and ‘b’ has frequency 2. ‘A’ has a lower ASCII value than ‘a’. Sorted order: “Aabb”.
Constraints:
1 <= T <= 10
1 <= N <= 1000
- Time Limit: 1 sec
Note:
Strings consist of both lowercase and uppercase alphabet characters. You do not need to print anything; it has already been taken care of. Just implement the function.
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