Last Stone Weight Problem Explanation
Given a collection of stones, each having a positive integer weight, perform the following operation: On each turn, select the two heaviest stones and smash them together. Assume the stones have weights 'x' and 'y' where 'x' <= 'y'. The outcomes of smashes are:
- If 'x' == 'y', both stones are destroyed.
- If 'x' != 'y', the stone with weight 'x' is destroyed, and the stone with weight 'y' is updated to 'y - x'.
Continue this process until at most one stone remains. Return the weight of the last stone, or 0 if no stones are left.
Input:
First line: Integer 'N', the number of stones.
Second line: 'N' space-separated integers representing the weights of the stones.
Output:
Print the weight of the final stone, or 0 if no stones remain.
Example:
Input:
N = 6
Weights = [2, 7, 4, 1, 8, 1]
Output:
1
Constraints:
1 <= N <= 10^5
1 <= W[i] <= 10^6
- Time Limit: 1 sec
Note:
Implement the function to solve the problem. No need for explicit printing or input reading as it's handled internally.
AnswerBot
10d
Implement a function to find the weight of the last stone remaining after smashing the heaviest stones together.
Create a max heap to store the weights of stones.
Repeatedly pop the two heaviest stones,...read more
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