ClaySys Junior Software Developer Interview Questions and Answers

Medium level questions from all sectors

Technical MCQ and easy coding questions

Q1. According to resume
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Artificial intelligence

Q1. Family background
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Intermediate aptitude questions .
No negative marking .
Written test held at JMR infotech

Q1. Mcq and coding questions . Mostly from Java and spring . Coding question is from Array and String (Find frequency )
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Q1. After the written test, face to face interview on technical and hr will be there .
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Easy level questions on string, linked list and array

Q1. Difference between TCP and UDP
Ans. 
TCP is a connection-oriented protocol while UDP is connectionless.
• TCP provides reliable, ordered, and error-checked delivery of data while UDP does not guarantee any of these.

• TCP is slower but more reliable while UDP is faster but less reliable.

• TCP is used for applications that require high reliability and accuracy such as email, file transfer, and web browsing while UDP is used for applications that require speed and ...read more
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Q2. Nibble swap program in C
Ans. 
A nibble swap program in C
• Nibble swap means swapping the 4-bit halves of a byte

• Use bitwise operators to perform the swap

• Example: unsigned char x = 0xAB; x = ((x & 0x0F) << 4) | ((x & 0xF0) >> 4);
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Q1. Reverse Linked List in C
Ans. 
Reverse a linked list in C language.
• Create three pointers: current, previous, and next.

• Traverse the linked list and change the direction of the pointers.

• Return the new head of the reversed linked list.
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Q2. Write an API call in C
Ans. 
API call in C
• Include the necessary header files

• Create a URL string with the required parameters

• Use the curl library to make the API call

• Handle the response data appropriately
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Programming on basics of C

Programming on basics of C

Q1. Salary details and location preference
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Q1. Middleware , dependency injection
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Q1. Subject and subject behaviour
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Duration:30 min
Question from percentage,ratios ,HCF/LCM etc.,
Logical reasoning, English

Q1. Reverse a string by making groups of given 'm' characters
Ans. 
Reverse a string by grouping 'm' characters together
• Iterate through the string in groups of 'm' characters

• Reverse each group of 'm' characters

• Concatenate the reversed groups to get the final reversed string
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Q1. General HR questions
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Q2. What is your family background?
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Q3. Why should we hire you?
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