C# Programming Questions and Answers

1

Select the output for the relevant code set:

1.

staticvoid Main(string[] args)

2.

{

3.

int a =4, b =5, c =7, u =9;

4.

int h;

5.

h =(Convert.ToInt32(u < b))+(a + b--)+2;

6.

Console.WriteLine(h);

7.

Console.WriteLine(b);

8.

Console.WriteLine(u < b);

9.

}

a

12,15,0

b

11,4,False

c

11,15,0

d

12,4,False

correct answer b

Step 1: Convert.ToInt32(u < b)(Evaluate result as 9 < 5 which is false in nature.So, solution is converted from 'false' to '0').

Step 2: (a + b--) evaluated as 4 + 5 = 9 + 2 =11. Step 3: u < b evaluated as 'False' without being converted to '0'.

Output : 11 4 False

2

Select the output for the following set of Code :

staticvoid Main(string[] args)

{

int a =8, b =6, c =10;

int d = a * c *2/ Convert.ToInt32(Math.Pow((c - b), 2));

if(d ==(c = Convert.ToInt32(Math.Sqrt(a * a + b * b)))&& c ==10)

{

Console.WriteLine("figure is hypotenuse");

}

else

{

Console.WriteLine("figure is square");

}

a

Figure is square

b

Figure is hypotenuse

c

False

d

None of the mentioned

correct answer a

Solving the expression for ‘c’ we get c==10 in if first condition as (c == Convert.ToInt32(Math.Sqrt(a * a + b * b))). The logical condition when d == (c = 10) suits here . Similarly, going for second condition where c ==10 as ‘&&’ operator exists between both given condition and at last both are evaluated to true as c == 10. So, only first statement is executed.
Output :Figure is square

3

Select the relevant output for the following set of code:

staticvoid Main(string[] args)

{

int a =4;

int b =5;

int c =6;

int d =8;

if(((a * b / c)+ d)>=((b * c + d )/ a))

{

Console.WriteLine("Line 1 - a is greater to b");

Console.WriteLine((a * b / c)+ d);

}

else

{

Console.WriteLine("Line 1 - a is not greater to b");

Console.WriteLine((b * c + d )/ a);

}

a

“Line 1 – a is greater to b”
11

b

“Line 1 – a is not greater to b”
9

c

Both are equal

d

None of the mentioned

correct answer a

Now, here in ‘if’ condition both conditions of parenthesis and hence evaluating operators based on parenthesis are tested.
for expression : ((a * b / c) + d)
Step 1 : (a*b/c) (Evaluating as 4*5/6 = 3)
Step 2 : ( (a*b/c) + d ) (Evaluating (3 + 8 = 11))
Result : 11
for expression : (b * c + d )/ a
Step 1 : (b*c + d) (Evaluating as 5*6 +8 = 38)
Step 2: (b*c + d) / a (Evaluating as 38 / 4 = 9)
Result : 9
The relational operator “>=” between both expressions check for largest figure and hence consecutively executes the if condition.
Output : Line 1 – a is greater to b.
11