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C Programming
What will the function rewind() do?
Reposition the file pointer to a character reverse.
Reposition the file pointer stream to end of file.
Reposition the file pointer to begining of that line.
Reposition the file pointer to begining of file.
Option D
rewind() takes the file pointer to the beginning of the file. so that the next I/O operation will take place at the beginning of the file.Example: rewind(FilePointer);
What will be the output of the program?
#include < stdio . h >#includeint main() { float i = 2.5; printf("%f, %d", floor(i), ceil(i)); return0; }
2, 3
2.000000, 3
2.000000, 0
2, 0
Answer :
Option C
Explanation :
Both ceil() and floor() return the integer found as a double. floor(2.5) returns the largest integral value(round down) that is not greater than 2.5. So output is 2.000000. ceil(2.5) returns 3, while converting the double to int it returns '0'. So, the output is '2.000000,
#include < stdio . h >int main() { int i; i = scanf("%d %d", &i, &i); printf("%d\n", i); return0; }
1
2
Garbage value
Error: cannot assign scanf to variable
Option B
scanf() returns the number of variables to which you are provding the input. i = scanf("%d %d", &i, &i); Here Scanf() returns 2. So i = 2. printf("%d\n", i); Here it prints 2.
#include < stdio . h >int main() { int i; char c; for(i=1; i <= 5; i++) { scanf("%c", &c); /* given input is 'b' */ ungetc(c, stdout); printf("%c", c); ungetc(c, stdin); } return0; }
bbbb
bbbbb
b
Error in ungetc statement.
The ungetc() function pushes the character c back onto the named input stream, which must be open for reading. This character will be returned on the next call to getc or fread for that stream. One character can be pushed back in all situations. A second call to ungetc without a call to getc will force the previous character to be forgotten.
#include < stdio . h >#includeint main() { char *i = "55.555"; int result1 = 10; float result2 = 11.111; result1 = result1+atoi(i); result2 = result2+atof(i); printf("%d, %f", result1, result2); return0; }
55, 55.555
66, 66.666600
65, 66.666000
55,55
Function atoi() converts the string to integer. Function atof() converts the string to float. result1 = result1+atoi(i); Here result1 = 10 + atoi(55.555); result1 = 10 + 55; result1 = 65; result2 = result2+atof(i); Here result2 = 11.111 + atof(55.555); result2 = 11.111 + 55.555000; result2 = 66.666000; So the output is "65, 66.666000" .
#include < stdio . h >#includeint main() { char dest[] = {97, 97, 0}; char src[] = "aaa"; int i; if((i = memcmp(dest, src, 2))==0) printf("Got it"); elseprintf("Missed"); return0; }
Missed
Got it
Error in memcmp statement
None of above
memcmp compares the first 2 bytes of the blocks dest and src as unsigned chars. So, the ASCII value of 97 is 'a'. if((i = memcmp(dest, src, 2))==0) When comparing the array dest and src as unsigned chars, the first 2 bytes are same in both variables.so memcmp returns '0'. Then, the if(0=0) condition is satisfied. Hence the output is "Got it".
Point out the error in the following program.
#include < stdio . h >int main() { fprintf("Ambition Box"); printf("%.ef", 2.0); return0; }
Error: unknown value in printf() statement.
Error: in fprintf() statement.
No error and prints "Ambition Box"
No error and prints "2.0"
Declaration Syntax: int fprintf (FILE *stream, const char *format [, argument, ...]);Example: fprintf(filestream, "%s %d %s", Name, Age, City);
#include < stdio . h >#include < string . h >int main() { char str1[] = "Learn through Ambition Box\0.com", str2[120]; char *p; p = (char*) memccpy(str2, str1, 'i', strlen(str1)); *p = '\0'; printf("%s", str2); return0; }
Error: in memccpy statement
Error: invalid pointer conversion
Error: invalid variable declaration
No error and prints "Learn through Ambi"
Declaration: void *memccpy(void *dest, const void *src, int c, size_t n); : Copies a block of n bytes from src to dest With memccpy(), the copying stops as soon as either of the following occurs: => the character 'i' is first copied into str2 => n bytes have been copied into str2
#include < stdio . h >int main() { char str[] = "Ambition box"; printf("%.#s %2s", str, str); return0; }
Error: in Array declaration
Error: printf statement
Error: unspecified character in printf
No error
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