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Aptitude
A and B invest in a business in the ratio 3 : 2. If 5% of the total profit goes to charity and A's share is Rs. 855, the total profit is :
500
1000
1500
2000
Let the total profit be Rs. 100.
After paying to charity, A's share = = Rs. 57.
If A's share is Rs. 57, total profit = Rs. 100.
If A's share is Rs. 855, total profit = = 1500.
What annual installment will discharge a debt of Rs 1092 due in 3 years at 12% simple interest?
325
545
560
550
Let each instalment be Rs.x .
Then, `[x + (x ** 12 ** 1)/100] + [ x + (x **12 ** 2)/100] + x =1092`
`( (28x)/25 ) + ( (31x)/25 ) + x = 1092`
`(28x + 31x + 25x) = (1092 ** 25)`
`x = (1092 ** 25)/84= 325`
Each instalment = Rs. 325
A mixture contains alcohol and water in the ratio 4 : 3. If 5 liters of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture.
10
12
15
18
Let the quantity of alcohol and water be 4x litres and 3x litres respectively
20x = 4(3x+5)
8x = 20
x = 2.5
Quantity of alcohol = (4 x 2.5) litres = 10 litres.
The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A ?
13
14
(A+B) - (B+C) = 12
A - C = 12.
C is younger than A by 12 years.
When 0.36 is written in simplest form, the sum of the numerator and the denominator is :
34
64
0.36 = 36/100 = 9/25.
Sum of the numerator and denominator is 9 + 25 = 34
Jack takes 20 minutes to jog around the race course one time, and 25 minutes to jog around a second time. What is his average speed in miles per hour for the whole jog if the course is 3 miles long?
6
8
9
Average speed = total distance / total time
Total distance covered = 6 miles; total time = 45 minutes = 0.75 hours
Average speed = 6/ 0.75 = 8 miles/hour
The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:
123
127
235
305
Required number = H.C.F. of (1657 - 6) and (2037 - 5)
= H.C.F. of 1651 and 2032 = 127.
The interger value of x at which inequality fails,
3x + 12 18
1
-7
-4
2
For x=2, 3(2)+ 12 = 0
6+12=18 so 18<18 is not possible since 18=18 and hence inequality fails
If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
Sunday
Saturday
Tuesday
Wednesday
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005.
So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005).
The maximum gap between two successive leap year is?
4
This can be illustrated with an example.
Ex: 1896 is a leap year.The next leap year comes in 1904 (1900 is not a leap year).
To eliminate this error, the Gregorian calendar stipulates that a year that is evenly divisible by 100 (for example, 1900) is a leap year only if it is also evenly divisible by 400. This is because they are evenly divisible by 100 but not by 400.
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